For oxyacid `HClO_(x)`, if x=y=z (x,y and z are natural numbers), then calculate the value of |x+y+z|. Where x=number of 'O' atoms
y=total number of lone pairs at central atom
z=total number of pi`(pi)` electrons in the oxyacid.

Explanation

To solve the problem for the oxyacid \( HClO_x \) where \( x = y = z \) (with \( x, y, z \) being natural numbers), we need to determine the values of \( x \), \( y \), and \( z \) based on the definitions provided:

1. **Identify \( x \)**: The number of oxygen atoms in the oxyacid.
2. **Identify \( y \)**: The total number of lone pairs on the central atom (chlorine in this case).
3. **Identify \( z \)**: The total number of pi electrons in the oxyacid.

### Step 1: Determine the value of \( x \)
Let's start with \( x = 2 \) (which means we are considering \( HClO_2 \)).

### Step 2: Analyze the structure of \( HClO_2 \)
The structure of \( HClO_2 \) (chlorous acid) can be represented as:
- One oxygen atom is double-bonded to chlorine.
- The other oxygen atom is single-bonded to chlorine and also bonded to hydrogen.

So, for \( HClO_2 \):
- **Number of oxygen atoms \( x = 2 \)**.

### Step 3: Determine \( y \) (lone pairs on the central atom)
In \( HClO_2 \):
- The chlorine atom (the central atom) has two lone pairs of electrons.

So, **total lone pairs \( y = 2 \)**.

### Step 4: Determine \( z \) (total number of pi electrons)
In \( HClO_2 \):
- There is one double bond between chlorine and one of the oxygen atoms. A double bond consists of one sigma bond and one pi bond.
- Each pi bond contains 2 pi electrons.

So, **total pi electrons \( z = 2 \)**.

### Step 5: Check if \( x = y = z \)
Now we have:
- \( x = 2 \)
- \( y = 2 \)
- \( z = 2 \)

Since \( x = y = z \), the condition is satisfied.

### Step 6: Calculate \( |x + y + z| \)
Now we can calculate:
\[ |x + y + z| = |2 + 2 + 2| = |6| = 6 \]

### Final Answer
Thus, the value of \( |x + y + z| \) is **6**.

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