How many monovalent oxygen atoms are preset in the mineral kinoite `(overset(+2)(Ca_(2))overset(+2)(Cu_(2))Si_(3)O_(10)*2H_(2)O)`?

Answer

To determine the number of monovalent oxygen atoms present in the mineral kinoite, we will analyze the chemical formula and the structure of the silicate anion.

### Step-by-Step Solution:

1. **Identify the Chemical Formula**: The chemical formula of kinoite is given as \( \text{Ca}_2\text{Cu}_2\text{Si}_3\text{O}_{10} \cdot 2\text{H}_2\text{O} \).

2. **Understand Monovalent Atoms**: A monovalent atom is one that forms one covalent bond. In the context of oxygen, this typically means that the oxygen atom is bonded to only one other atom.

3. **Analyze the Silicate Anion**: The silicate part of the mineral is represented by \( \text{Si}_3\text{O}_{10} \). This indicates that there are 10 oxygen atoms associated with the three silicon atoms.

4. **Draw the Structure**: In the silicate structure, each silicon atom is typically bonded to four oxygen atoms. However, in this case, we need to identify which of these oxygen atoms are monovalent.

5. **Count the Monovalent Oxygen Atoms**:
- In the structure of \( \text{Si}_3\text{O}_{10} \), there are 10 oxygen atoms.
- Out of these, some oxygen atoms are bonded to silicon (which would be bivalent) and some are bonded to other atoms or are terminal (which would be monovalent).
- By analyzing the structure, we find that there are 8 oxygen atoms that are bonded to only one silicon atom.

6. **Conclusion**: Therefore, the total number of monovalent oxygen atoms present in the mineral kinoite is **8**.

### Final Answer:
The number of monovalent oxygen atoms in kinoite is **8**.

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