How many moles of NaOH are required to react with one mole of solid `N_(2)O_(5)`?

Answer

To determine how many moles of NaOH are required to react with one mole of solid \( N_2O_5 \), we need to follow these steps:

### Step 1: Write the Balanced Chemical Equation
The first step is to write the balanced chemical equation for the reaction between sodium hydroxide (NaOH) and dinitrogen pentoxide (\( N_2O_5 \)). The reaction can be represented as follows:

\[ N_2O_5 + NaOH \rightarrow NaNO_3 + H_2O \]

### Step 2: Balance the Reaction
Next, we need to balance the chemical equation. In the unbalanced equation, we have:

- 2 nitrogen (N) atoms in \( N_2O_5 \)
- Each \( NaNO_3 \) contains 1 nitrogen atom, so we need 2 \( NaNO_3 \) to balance the nitrogen.

This gives us:

\[ N_2O_5 + 2 NaOH \rightarrow 2 NaNO_3 + H_2O \]

### Step 3: Count the Moles of Reactants and Products
From the balanced equation, we can see that:

- 1 mole of \( N_2O_5 \) reacts with 2 moles of NaOH.
- The products formed are 2 moles of sodium nitrate (NaNO3) and 1 mole of water (H2O).

### Step 4: Conclusion
Thus, the number of moles of NaOH required to react with one mole of solid \( N_2O_5 \) is:

\[ \text{2 moles of NaOH} \]

### Final Answer
2 moles of NaOH are required to react with one mole of solid \( N_2O_5 \).

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