Consider the structure of `Al_(2)Me_(6)` compound and find the value of `(x-y)/(z)` where `x=` maximum number of atoms that can lie in place having terminal `(Al-Me)` bonds
`y=` total number of `3c-2e^(-)` bonds
`z=` total number of atoms that are `sp^(3)` hydrized.

Explanation

To solve the problem regarding the compound \( Al_2Me_6 \), we will follow these steps:

### Step 1: Determine the maximum number of atoms that can lie in a place having terminal \( Al-Me \) bonds (x).

In the structure of \( Al_2Me_6 \), we can visualize it as follows:
- There are two aluminum (Al) atoms.
- Each aluminum atom is bonded to multiple methyl (Me) groups.

Counting the terminal \( Al-Me \) bonds:
- Each aluminum atom can form bonds with the methyl groups.
- In total, there are 10 terminal \( Al-Me \) bonds.

Thus, the maximum number of atoms that can lie in a place having terminal \( Al-Me \) bonds is:
\[ x = 10 \]

### Step 2: Count the total number of 3-center 2-electron bonds (y).

In the structure of \( Al_2Me_6 \):
- A 3-center 2-electron bond involves three atoms sharing two electrons.
- In this compound, there are 2 such bonds formed between the two aluminum atoms and the bridging carbon atoms.

Thus, the total number of 3-center 2-electron bonds is:
\[ y = 2 \]

### Step 3: Calculate the total number of atoms that are \( sp^3 \) hybridized (z).

In the structure of \( Al_2Me_6 \):
- Each methyl group (Me) contributes to the \( sp^3 \) hybridization of the carbon atom.
- The two aluminum atoms are also involved in hybridization.

Counting the \( sp^3 \) hybridized atoms:
- There are 8 atoms in total that are \( sp^3 \) hybridized (including the two aluminum and six carbon atoms from the methyl groups).

Thus, the total number of atoms that are \( sp^3 \) hybridized is:
\[ z = 8 \]

### Step 4: Calculate the value of \( \frac{x - y}{z} \).

Now we can substitute the values of \( x \), \( y \), and \( z \) into the expression:
\[ \frac{x - y}{z} = \frac{10 - 2}{8} = \frac{8}{8} = 1 \]

### Final Answer:
The value of \( \frac{x - y}{z} \) is \( 1 \).

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