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To avoid the precipitation of hydroxides...

To avoid the precipitation of hydroxides of `Ni^(2+),Co^(2+),Zn^(2+) and Mn^(2+)` along with those of `Fe^(3+),Al^(3+) and Cr^(3+)` the third group cations, solution should be:

A

Heated with a few drops of conc. `HNO_(3)`

B

Treated with excess of `NH_(4)Cl`

C

Concentrated to small volume

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of avoiding the precipitation of hydroxides of Ni²⁺, Co²⁺, Zn²⁺, and Mn²⁺ along with those of Fe³⁺, Al³⁺, and Cr³⁺, we can follow these steps: ### Step 1: Understand the Groups of Cations - **Group 3 Cations**: Fe³⁺, Al³⁺, Cr³⁺ - **Group 4 Cations**: Ni²⁺, Co²⁺, Zn²⁺, Mn²⁺ ### Step 2: Identify the Hydroxide Precipitation - Hydroxides of Group 3 cations (Fe³⁺, Al³⁺, Cr³⁺) have lower solubility products compared to those of Group 4 cations (Ni²⁺, Co²⁺, Zn²⁺, Mn²⁺). This means that under certain conditions, Group 3 hydroxides will precipitate before Group 4 hydroxides. ### Step 3: Use of Ammonium Chloride (NH₄Cl) - To prevent the precipitation of hydroxides of Group 4 cations while allowing the Group 3 cations to remain in solution, we can add **excess NH₄Cl** to the solution. ### Step 4: Common Ion Effect - When NH₄Cl is added, it dissociates into NH₄⁺ and Cl⁻ ions. The NH₄⁺ ion will affect the dissociation of NH₄OH (ammonium hydroxide) in the solution. - The presence of NH₄⁺ (common ion) reduces the degree of dissociation of NH₄OH, which means that the concentration of OH⁻ ions in the solution is limited. ### Step 5: Control of Hydroxide Ion Concentration - By controlling the concentration of OH⁻ ions through the common ion effect, we can ensure that the concentration of OH⁻ is just sufficient to reach the solubility product constant of the Group 3 hydroxides, preventing their precipitation while keeping the Group 4 cations in solution. ### Conclusion - Therefore, to avoid the precipitation of hydroxides of Ni²⁺, Co²⁺, Zn²⁺, and Mn²⁺ along with those of Fe³⁺, Al³⁺, and Cr³⁺, the solution should be treated with **excess NH₄Cl**. ### Final Answer The solution should be treated with excess NH₄Cl. ---
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