On heating a mixture of NaBr and conc. `H_(2)SO_(4)` we obtain:

Options

A. `HOBr`
B. `HB r`
C. `Br_(2)`
D. `HBrO_(3)`

Answer

To solve the problem of what happens when a mixture of NaBr and concentrated H₂SO₄ is heated, we can break down the reaction step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are sodium bromide (NaBr) and concentrated sulfuric acid (H₂SO₄).

### Step 2: Understand the Reaction Mechanism
When NaBr is heated with concentrated H₂SO₄, bromide ions (Br⁻) act as reducing agents. This means they can donate electrons to another substance, in this case, sulfuric acid.

### Step 3: Determine the Products
The reaction between NaBr and concentrated H₂SO₄ leads to the formation of several products:
1. Sodium hydrogen sulfate (NaHSO₄)
2. Bromine (Br₂)
3. Sulfur dioxide (SO₂)
4. Water (H₂O)

### Step 4: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction can be written as:
\[ 2 \text{NaBr} + \text{conc. H}_2\text{SO}_4 \rightarrow \text{NaHSO}_4 + \text{Br}_2 + \text{SO}_2 + \text{H}_2\text{O} \]

### Step 5: Conclusion
Upon heating a mixture of NaBr and concentrated H₂SO₄, the products formed are sodium hydrogen sulfate, bromine, sulfur dioxide, and water.

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