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An inorganic salt is strongly heated. Th...

An inorganic salt is strongly heated. The residue is yellow when hot and white when cold. The salt contains:

A

`Pb^(2+)`

B

`Zn^(2+)`

C

`Hg^(2+)`

D

`NH_(4)^(+)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the behavior of the inorganic salt when it is heated. The key observations are that the residue is yellow when hot and white when cold. Based on this information, we can deduce the identity of the salt. ### Step-by-Step Solution: 1. **Identify the Color Change**: - The residue is yellow when hot and white when cold. This indicates that the substance undergoes a change in color with temperature. 2. **Consider Possible Compounds**: - One common compound that exhibits this behavior is zinc oxide (ZnO). Zinc oxide is known to appear yellow when heated and turns white upon cooling. 3. **Relate to a Precursor Salt**: - Zinc oxide can be obtained by heating zinc carbonate (ZnCO₃). The reaction for this process is: \[ \text{ZnCO}_3 \, (s) \xrightarrow{\text{heat}} \text{ZnO} \, (s) + \text{CO}_2 \, (g) \] - Here, zinc carbonate decomposes upon heating to form zinc oxide and carbon dioxide gas. 4. **Conclusion About the Salt**: - Since the residue after heating is zinc oxide (which is yellow when hot and white when cold), we can conclude that the original salt must contain the zinc ion (Zn²⁺). 5. **Final Answer**: - Therefore, the salt contains the cation Zn²⁺.
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