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A white, sublimable inorganic substance ...

A white, sublimable inorganic substance gives a brown precipitate on treatment with nessler's reagent and a whiite precipitate (soluble in `NH_(3)`) with ann `AgNO_(3)` solution. The substance is :

A

`Hg_(2)Cl_(2)`

B

`HgCl_(2)`

C

`As_(2)O_(3)`

D

`NH_(4)Cl`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the information given about the white sublimable inorganic substance and the reactions it undergoes. ### Step 1: Identify the Reactions The substance gives two key reactions: 1. A brown precipitate with Nessler's reagent. 2. A white precipitate that is soluble in ammonia when treated with AgNO3. ### Step 2: Understand Nessler's Reagent Nessler's reagent is K2HgI4 in KOH, which is used to detect ammonia (NH3) or ammonium ions (NH4+). When NH3 or NH4+ is present, it forms a brown precipitate known as the iodide of melon's base (Hg2I2·NH2). ### Step 3: Analyze the Brown Precipitate The formation of a brown precipitate indicates the presence of ammonium ions (NH4+). This suggests that the white sublimable inorganic substance is likely to contain ammonium ions. ### Step 4: Examine the White Precipitate with AgNO3 When the substance reacts with AgNO3, it forms a white precipitate. The reaction can be represented as: \[ \text{NH}_4\text{Cl} + \text{AgNO}_3 \rightarrow \text{AgCl} \downarrow + \text{NH}_4\text{NO}_3 \] Here, AgCl is the white precipitate formed. ### Step 5: Solubility of the White Precipitate in Ammonia The white precipitate (AgCl) is soluble in ammonia, forming a colorless complex: \[ \text{AgCl} + 2\text{NH}_3 \rightarrow \text{[Ag(NH}_3\text{)}_2]^+ + \text{Cl}^- \] This confirms that the white precipitate is indeed AgCl, which is consistent with the presence of ammonium ions. ### Step 6: Conclusion Based on the reactions and the analysis, the white sublimable inorganic substance that gives a brown precipitate with Nessler's reagent and a white precipitate soluble in ammonia is **ammonium chloride (NH4Cl)**. ### Final Answer The substance is **NH4Cl** (ammonium chloride). ---
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