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An aqueous solution of a substance gives...

An aqueous solution of a substance gives a white percipitate on treatment with dil `HCl`, which dissole on heating. On passing `H_(2)S` in hot acidic solution a black percipitate is formed. The substance is:

A

`Hg_(2)^(2+)` salt

B

`Hg^(2+)` salt

C

`Ag^(+)` salt

D

`Pb^(2+)` salt

Text Solution

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The correct Answer is:
To solve the problem step-by-step, we will analyze the given information and identify the substance based on the reactions described. ### Step 1: Analyze the reaction with dilute HCl When an aqueous solution of the substance is treated with dilute hydrochloric acid (HCl), a white precipitate is formed. This indicates that the substance likely contains a cation that forms an insoluble salt with chloride ions. **Hint:** Look for cations that form white precipitates with chloride ions. ### Step 2: Identify the white precipitate The white precipitate formed can be identified as lead(II) chloride (PbCl2), which is known to be a white solid. This suggests that the substance could be lead(II) ions (Pb²⁺). **Hint:** Remember that PbCl2 is a common white precipitate formed from Pb²⁺ ions. ### Step 3: Heating the precipitate The problem states that the white precipitate dissolves upon heating. Lead(II) chloride (PbCl2) is known to be soluble in hot water, confirming that our assumption about the substance being lead(II) ions is correct. **Hint:** Consider the solubility of the precipitate in hot conditions. ### Step 4: Passing H2S in hot acidic solution Next, when hydrogen sulfide (H2S) is passed through the hot acidic solution, a black precipitate is formed. This black precipitate is likely lead(II) sulfide (PbS), which is known to be a black solid. **Hint:** Identify the black precipitate formed with H2S and relate it to the cation present. ### Step 5: Conclusion Based on the observations: 1. The formation of a white precipitate (PbCl2) with dilute HCl. 2. The dissolution of that precipitate upon heating. 3. The formation of a black precipitate (PbS) upon passing H2S in an acidic medium. We conclude that the substance is lead(II) salt (Pb²⁺). ### Final Answer: The substance is lead(II) salt (Pb²⁺).
To solve the problem step-by-step, we will analyze the given information and identify the substance based on the reactions described. ### Step 1: Analyze the reaction with dilute HCl When an aqueous solution of the substance is treated with dilute hydrochloric acid (HCl), a white precipitate is formed. This indicates that the substance likely contains a cation that forms an insoluble salt with chloride ions. **Hint:** Look for cations that form white precipitates with chloride ions. ### Step 2: Identify the white precipitate ...
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