Which of the following precipitate is soluble in excess of `NH_(3)` solution?

Options

A. `Pb(OH)_(2)`
B. `Fe(OH)_(2)`
C. `Ni(OH)_(2)`
D. `Ag_(2)S`

Explanation

To determine which precipitate is soluble in excess ammonia solution, we will analyze the solubility of various hydroxides in ammonia.

### Step-by-Step Solution:

1. **Identify the Precipitates**:
The question mentions several precipitates:
- Lead hydroxide (Pb(OH)₂) - White precipitate
- Iron(II) hydroxide (Fe(OH)₂) - Dirty green precipitate
- Silver sulfide (Ag₂S) - Black precipitate
- Nickel hydroxide (Ni(OH)₂) - Green precipitate

2. **Analyze Solubility in Ammonia**:
- **Lead Hydroxide (Pb(OH)₂)**: This compound is known to be insoluble in excess ammonia.
- **Iron(II) Hydroxide (Fe(OH)₂)**: Similarly, this is also insoluble in excess ammonia.
- **Silver Sulfide (Ag₂S)**: This compound is insoluble in excess ammonia as well.
- **Nickel Hydroxide (Ni(OH)₂)**: Nickel hydroxide is known to dissolve in excess ammonia, forming a complex ion.

3. **Conclusion**:
Among the given options, only nickel hydroxide (Ni(OH)₂) is soluble in excess ammonia solution, forming a complex ion.

### Final Answer:
**Nickel hydroxide (Ni(OH)₂)** is the precipitate that is soluble in excess ammonia solution.

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