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A very dilute acidic solution of Cd^(2+)...

A very dilute acidic solution of `Cd^(2+) and Ni^(2+)` gives only yellow ppt. of CdS on passing `H_(2)S`, this is due to

A

Solubility product `(K_(sp))` of CdS is more than that of NiS

B

Solubility product `(K_(sp))` of CdS is less than that of NiS

C

`Cd^(2+)` belongs to `II B` group while `Ni^(2+)` belongs to `IV^(th)` group

D

CdS is insoluble in yellow ammonium sulphide (YAS)

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The correct Answer is:
To solve the problem, we need to analyze why a very dilute acidic solution containing both `Cd^(2+)` and `Ni^(2+)` gives only a yellow precipitate of `CdS` when `H2S` is passed through it. ### Step-by-Step Solution: 1. **Identify the Ions Present**: - The solution contains `Cd^(2+)` (cadmium ions) and `Ni^(2+)` (nickel ions). 2. **Understanding the Reaction with H2S**: - When `H2S` is passed through the solution, it provides `S^(2-)` ions which can react with the metal cations to form metal sulfides. - The sulfides formed are `CdS` and `NiS`. 3. **Precipitation of Metal Sulfides**: - `CdS` is known to form a yellow precipitate, while `NiS` forms a black precipitate. - The observation states that only a yellow precipitate of `CdS` is formed. 4. **Solubility Product (Ksp) Consideration**: - The formation of a precipitate depends on the solubility product constant (Ksp) of the metal sulfides. - The Ksp for `CdS` is significantly lower than that of `NiS`, indicating that `CdS` is less soluble than `NiS`. 5. **Concentration of Sulfide Ions**: - The concentration of sulfide ions required to precipitate `CdS` is lower than that required for `NiS` due to the difference in their Ksp values. - Therefore, at a lower concentration of sulfide ions, `CdS` will precipitate first before `NiS`. 6. **Conclusion**: - Since the solution is very dilute and both `Cd^(2+)` and `Ni^(2+)` are present in similar concentrations, the lower Ksp of `CdS` means it will precipitate first when `H2S` is introduced, leading to the formation of the yellow precipitate. 7. **Final Statement**: - The reason why only a yellow precipitate of `CdS` is formed is that the solubility product (Ksp) of `CdS` is less than that of `NiS`, allowing `CdS` to precipitate at lower concentrations of sulfide ions.

To solve the problem, we need to analyze why a very dilute acidic solution containing both `Cd^(2+)` and `Ni^(2+)` gives only a yellow precipitate of `CdS` when `H2S` is passed through it. ### Step-by-Step Solution: 1. **Identify the Ions Present**: - The solution contains `Cd^(2+)` (cadmium ions) and `Ni^(2+)` (nickel ions). 2. **Understanding the Reaction with H2S**: ...
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