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Which of the following compounds is/are ...

Which of the following compounds is/are partially soluble or insoluble in `NH_(4)OH` solution:
(1) `Fe(OH)_(3)`
(2) `Ag_(2)CrO_(4)`
(3) `Al(OH)_(3)`
(4) `Ag_(2)CO_(3)`
(5) `Ni(OH)_(2)`

A

1,3,5

B

2,3,4

C

1,3

D

2,3,5

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds are partially soluble or insoluble in ammonium hydroxide (NH₄OH) solution, we will analyze each compound one by one. ### Step 1: Analyze `Fe(OH)₃` - **Reaction with NH₄OH**: Ferric hydroxide (Fe(OH)₃) is formed when Fe³⁺ ions react with NH₄OH. - **Solubility**: Fe(OH)₃ is known to be insoluble in NH₄OH. It precipitates as a brown solid. **Conclusion**: `Fe(OH)₃` is insoluble in NH₄OH. ### Step 2: Analyze `Ag₂CrO₄` - **Reaction with NH₄OH**: Silver chromate (Ag₂CrO₄) does not react significantly with NH₄OH. - **Solubility**: It is generally considered to be soluble in ammonium hydroxide due to the formation of complex ions. **Conclusion**: `Ag₂CrO₄` is soluble in NH₄OH. ### Step 3: Analyze `Al(OH)₃` - **Reaction with NH₄OH**: Aluminum hydroxide (Al(OH)₃) is formed when Al³⁺ ions react with NH₄OH. - **Solubility**: Al(OH)₃ is known to be partially soluble in NH₄OH, forming soluble aluminate ions. **Conclusion**: `Al(OH)₃` is partially soluble in NH₄OH. ### Step 4: Analyze `Ag₂CO₃` - **Reaction with NH₄OH**: Silver carbonate (Ag₂CO₃) does not react significantly with NH₄OH. - **Solubility**: It is generally considered to be soluble in ammonium hydroxide. **Conclusion**: `Ag₂CO₃` is soluble in NH₄OH. ### Step 5: Analyze `Ni(OH)₂` - **Reaction with NH₄OH**: Nickel hydroxide (Ni(OH)₂) is formed when Ni²⁺ ions react with NH₄OH. - **Solubility**: Ni(OH)₂ is known to be insoluble in NH₄OH. **Conclusion**: `Ni(OH)₂` is insoluble in NH₄OH. ### Final Summary Based on the analysis: - `Fe(OH)₃` - Insoluble - `Ag₂CrO₄` - Soluble - `Al(OH)₃` - Partially soluble - `Ag₂CO₃` - Soluble - `Ni(OH)₂` - Insoluble ### Answer The compounds that are partially soluble or insoluble in NH₄OH solution are: 1. `Fe(OH)₃` 2. `Al(OH)₃` 3. `Ni(OH)₂` Thus, the correct options are (1) and (3).
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