A mixture of ferric alum, chrome alum and potash alum is dissolved in water and treated with an excess of `NH_(3)` solution annd warmed with a mixture of NaOH and `H_(2)O_(2)` and filtered. We will get:

Options

A. a green residue ad a yellow filtrate
B. a brown residue and a yellow filtrate
C. a brownn residue ad a green filtrate
D. a blue residue and a green filtrate

Answer

To solve the problem, we will analyze the reactions that occur when a mixture of ferric alum, chrome alum, and potash alum is treated with ammonia, sodium hydroxide, and hydrogen peroxide. Here’s a step-by-step breakdown of the process:

### Step 1: Dissolving the Mixture
- **Action**: The mixture of ferric alum (FeAl(SO4)2·12H2O), chrome alum (CrAl(SO4)2·12H2O), and potash alum (KAl(SO4)2·12H2O) is dissolved in water.
- **Result**: This results in the formation of their respective metal hydroxides in solution:
- Ferric hydroxide: Fe(OH)3
- Chrome hydroxide: Cr(OH)3
- Potassium hydroxide: KOH

**Hint**: Remember that when metal salts dissolve in water, they typically dissociate into their respective ions.

### Step 2: Treatment with Ammonia
- **Action**: The solution is treated with an excess of NH3 (ammonia).
- **Result**:
- KOH remains soluble in water.
- Cr(OH)3 becomes soluble in the presence of excess ammonia, forming a complex ion.
- Fe(OH)3 remains insoluble and precipitates out as a brown solid.

**Hint**: Ammonia can increase the solubility of certain metal hydroxides by forming complex ions.

### Step 3: Warming with NaOH and H2O2
- **Action**: The mixture is then warmed with a mixture of NaOH and H2O2.
- **Result**:
- The Fe(OH)3 precipitate remains unchanged and continues to be a brown precipitate.
- Cr(OH)3 reacts with NaOH and H2O2 to form sodium chromate (Na2CrO4), which is yellow in color.

**Hint**: The presence of hydrogen peroxide can oxidize Cr(OH)3 to form chromate ions.

### Step 4: Filtration
- **Action**: The mixture is filtered.
- **Result**:
- The brown precipitate of Fe(OH)3 is collected on the filter paper.
- The yellow solution containing Na2CrO4 (sodium chromate) passes through as the filtrate.

**Hint**: Filtration separates solids from liquids, allowing you to collect the precipitate and the soluble components separately.

### Final Result
- After filtration, we observe:
- A **brown residue** (Fe(OH)3) on the filter paper.
- A **yellow colored filtrate** (Na2CrO4) in the beaker.

### Conclusion
The final products obtained from the treatment of the mixture are:
- Brown residue (Fe(OH)3)
- Yellow colored filtrate (Na2CrO4)

**Final Answer**: Brown residue and yellow colored filtrate.