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Fe^(2+) and Fe^(3+) can be distinguished...

`Fe^(2+) and Fe^(3+)` can be distinguished by

A

`K_(3)[Fe(CN)_(6)]`

B

`K_(4)[Fe(CN)_(6)]`

C

`KSCN`

D

All are correct

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The correct Answer is:
To distinguish between Fe²⁺ and Fe³⁺ ions, we can perform a series of reactions with specific reagents. Here’s a step-by-step solution: ### Step 1: Reaction with K₃[Fe(CN)₆] - **Fe²⁺ Reaction**: When Fe²⁺ reacts with potassium ferricyanide (K₃[Fe(CN)₆]), it forms a blue precipitate known as Turnbull's blue (KFe[Fe(CN)₆]). - **Fe³⁺ Reaction**: When Fe³⁺ reacts with the same reagent, it forms a brown precipitate (Fe[Fe(CN)₆]). ### Step 2: Reaction with K₄[Fe(CN)₆] - **Fe²⁺ Reaction**: When Fe²⁺ reacts with potassium ferrocyanide (K₄[Fe(CN)₆]), it produces a white precipitate (K₂[Fe(Fe(CN)₆)]). - **Fe³⁺ Reaction**: When Fe³⁺ reacts with the same reagent, it produces a blue precipitate known as Prussian blue (KFe[Fe(CN)₆]). ### Step 3: Reaction with KSCN - **Fe²⁺ Reaction**: There is no significant reaction between Fe²⁺ and potassium thiocyanate (KSCN), meaning no precipitate is formed. - **Fe³⁺ Reaction**: When Fe³⁺ reacts with KSCN, it forms a blood-red colored complex (Fe(SCN)³⁺). ### Conclusion By observing the color and type of precipitate formed in these reactions, we can distinguish between Fe²⁺ and Fe³⁺ ions. The distinct colors of the precipitates and the formation of a complex with KSCN for Fe³⁺ only help in identifying the oxidation states of iron. ### Final Answer Fe²⁺ and Fe³⁺ can be distinguished by their reactions with K₃[Fe(CN)₆], K₄[Fe(CN)₆], and KSCN, which produce different colored precipitates and complexes. ---
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