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Which of the following pairs of cations ...

Which of the following pairs of cations cannot be separated by adding `NH_(4)Cl` and `NH_(4)OH` to the mixture and then passing `H_(2)S` through it?

A

`Ca^(2+) and Ni^(2+)`

B

`Mg^(2+) and Mn^(2+)`

C

`Ni^(2+) and Mn^(2+)`

D

`Co^(2+) and Zn^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which pairs of cations cannot be separated by adding `NH₄Cl` and `NH₄OH` to the mixture and then passing `H₂S` through it, we need to analyze the behavior of the given cations when treated with these reagents. ### Step-by-Step Solution: 1. **Identify the Cations and Their Groups**: - The cations provided in the question are: - Pair 1: Calcium (Ca²⁺) and Nickel (Ni²⁺) - Pair 2: Magnesium (Mg²⁺) and Manganese (Mn²⁺) - Pair 3: Nickel (Ni²⁺) and Manganese (Mn²⁺) - Pair 4: Cobalt (Co²⁺) and Zinc (Zn²⁺) 2. **Understand the Grouping of Cations**: - In qualitative analysis, cations are grouped based on their solubility in certain reagents. The reagents `NH₄Cl` and `NH₄OH` are used to precipitate certain cations when `H₂S` is passed through the solution. - The fourth group cations that are precipitated as sulfides include Ni²⁺, Mn²⁺, Co²⁺, and Zn²⁺. 3. **Analyze Each Pair**: - **Pair 1: Ca²⁺ and Ni²⁺**: - Ca²⁺ is a fifth group cation and will not precipitate with `H₂S`. Ni²⁺ is a fourth group cation and will precipitate as NiS. - **Conclusion**: They can be separated. - **Pair 2: Mg²⁺ and Mn²⁺**: - Mg²⁺ is a sixth group cation and will not precipitate with `H₂S`. Mn²⁺ is a fourth group cation and will precipitate as MnS. - **Conclusion**: They can be separated. - **Pair 3: Ni²⁺ and Mn²⁺**: - Both Ni²⁺ and Mn²⁺ are fourth group cations and will precipitate as NiS and MnS, respectively. - **Conclusion**: They cannot be separated. - **Pair 4: Co²⁺ and Zn²⁺**: - Both Co²⁺ and Zn²⁺ are also fourth group cations and will precipitate as CoS and ZnS, respectively. - **Conclusion**: They cannot be separated. 4. **Final Answer**: - The pairs of cations that cannot be separated by adding `NH₄Cl` and `NH₄OH` and then passing `H₂S` through the mixture are: - **Nickel (Ni²⁺) and Manganese (Mn²⁺)** - **Cobalt (Co²⁺) and Zinc (Zn²⁺)**
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VK JAISWAL ENGLISH-QUALITATIVE INORGANIC ANALYSIS-ONE OR MORE ANSWER IS/ARE CORRECT
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