`Al_(2)(SO_(4))_(3)+NH_(4)OH to X`
Select the correct statement(s) about compound X:

Options

A. X is a white coloured compound
B. X is insoluble in excess of `NH_(4)OH`
C. X is soluble in NaOH
D. X can be used an an antacid

Answer

To solve the problem, we need to analyze the reaction between aluminum sulfate \((Al_2(SO_4)_3)\) and ammonium hydroxide \((NH_4OH)\) to determine the product \(X\) and the properties of this compound.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are aluminum sulfate \((Al_2(SO_4)_3)\) and ammonium hydroxide \((NH_4OH)\).

2. **Write the Reaction**:
- When aluminum sulfate reacts with ammonium hydroxide, the products formed are aluminum hydroxide \((Al(OH)_3)\) and ammonium sulfate \((NH_4)_2SO_4\).
- The balanced chemical equation for the reaction is:
\[ Al_2(SO_4)_3 + 6 NH_4OH \rightarrow 2 Al(OH)_3 + 3 (NH_4)_2SO_4 \]

3. **Identify the Product \(X\)**:
- The compound \(X\) formed in this reaction is aluminum hydroxide \((Al(OH)_3)\).

4. **Determine the Properties of \(X\)**:
- **Color**: Aluminum hydroxide is known to form a white gelatinous precipitate, so \(X\) is a white colored compound.
- **Solubility in Ammonium Hydroxide**: Aluminum hydroxide is insoluble in excess ammonium hydroxide, confirming that statement B is true.
- **Solubility in Sodium Hydroxide**: Aluminum hydroxide is soluble in sodium hydroxide, forming a soluble aluminate complex, making statement C true.
- **Use as Antacid**: Aluminum hydroxide can neutralize stomach acid, thus it can be used as an antacid, making statement D true.

5. **Conclusion**:
- All statements about compound \(X\) are correct:
- A: \(X\) is a white colored compound (True)
- B: \(X\) is insoluble in excess \(NH_4OH\) (True)
- C: \(X\) is soluble in \(NaOH\) (True)
- D: \(X\) can be used as an antacid (True)

### Final Answer:
All options A, B, C, and D are correct regarding compound \(X\).