The most electropositive element possesses the electronic configuration:

Options

A. `[He]2s^(1)`
B. `[Ne]3s^(2)`
C. `[Xe]6s^(1)`
D. `[Xe]6s^(2)`

Answer

To determine the most electropositive element based on its electronic configuration, we need to analyze the given options and understand the concept of electropositivity.

### Step-by-Step Solution:

1. **Understanding Electropositivity**:
- Electropositive elements are those that can easily lose electrons to form positive ions. This property is typically found in metals, especially alkali and alkaline earth metals.

2. **Reviewing Electronic Configurations**:
- The electronic configurations provided in the options include:
- 2s¹
- 3s²
- 6s²
- 6s¹

3. **Identifying the Group Trends**:
- As we move down a group in the periodic table, the atomic size increases due to the addition of electron shells. This increase in size makes it easier for the outermost electrons to be removed, thus increasing electropositivity.

4. **Analyzing the Options**:
- **2s¹**: This configuration corresponds to lithium (Li), which is electropositive but not the most electropositive.
- **3s²**: This configuration corresponds to magnesium (Mg), which is also not the most electropositive.
- **6s²**: This configuration corresponds to radon (Rn), which is a noble gas with a filled outer shell, making it less likely to lose electrons.
- **6s¹**: This configuration corresponds to francium (Fr), which is at the bottom of the alkali metals group and has the largest atomic size, making it the most electropositive element.

5. **Conclusion**:
- Among the given options, the configuration **6s¹** corresponds to francium, which is the most electropositive element due to its large atomic size and the ease of losing the single outer electron.

### Final Answer:
The most electropositive element possesses the electronic configuration **6s¹**.

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