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The ionic radii of Li^(+), Be^(2+) and B...

The ionic radii of `Li^(+)`, `Be^(2+) and B^(3+)` follow the order:

A

`Be^(2+) gt B^(3+) gt Li^(+)`

B

`Li^(+) gt B^(3+) gt Be^(2+) `

C

`B^(3+) gt Be^(2+) gt Li^(+)`

D

`Li^(+) gt Be^(2+) gt B^(3+) `

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of ionic radii for the ions \( Li^{+} \), \( Be^{2+} \), and \( B^{3+} \), we can follow these steps: ### Step 1: Identify the Ions The ions we are considering are: - \( Li^{+} \) (Lithium ion) - \( Be^{2+} \) (Beryllium ion) - \( B^{3+} \) (Boron ion) ### Step 2: Determine the Number of Electrons Each of these ions is formed from their respective neutral atoms by losing electrons: - Lithium (Li) has 3 electrons, so \( Li^{+} \) has 2 electrons. - Beryllium (Be) has 4 electrons, so \( Be^{2+} \) has 2 electrons. - Boron (B) has 5 electrons, so \( B^{3+} \) has 2 electrons. Since all three ions have lost electrons and now have the same number of electrons (2), they are classified as isoelectronic species. ### Step 3: Understand Isoelectronic Species Isoelectronic species are ions or atoms that have the same number of electrons. In this case, \( Li^{+} \), \( Be^{2+} \), and \( B^{3+} \) all have 2 electrons. ### Step 4: Analyze the Charge and Size Relationship In isoelectronic species, the size of the ion is inversely related to the charge on the ion: - \( Li^{+} \) has a +1 charge. - \( Be^{2+} \) has a +2 charge. - \( B^{3+} \) has a +3 charge. As the positive charge increases, the effective nuclear charge experienced by the electrons also increases, pulling the electrons closer to the nucleus and resulting in a smaller ionic radius. ### Step 5: Order the Ionic Radii Based on the increasing positive charge: - \( Li^{+} \) will have the largest ionic radius because it has the least positive charge. - \( Be^{2+} \) will be smaller than \( Li^{+} \) but larger than \( B^{3+} \). - \( B^{3+} \) will have the smallest ionic radius due to the highest positive charge. Thus, the order of ionic radii is: \[ Li^{+} > Be^{2+} > B^{3+} \] ### Final Answer The ionic radii of \( Li^{+} \), \( Be^{2+} \), and \( B^{3+} \) follow the order: \[ Li^{+} > Be^{2+} > B^{3+} \] ---
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