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The formation of the oxide ion O^(2-) (g...

The formation of the oxide ion `O^(2-)` (g) requires first an exothermic and then an endothermic step as shown below :
`O (g) + e^(-)= O^(-) (g), DeltaH^(@) = - 142 kJ moI^(-1)`
`O(g)+e^(-)toO^(2-)(g),DeltaH^(@)=844kJmol^(-1)`
This is because

A

`O^(-)` ion has comparatively larger size than oxygen atom

B

oxygen has high electron affinity

C

`O^(-)` ion will tend to resist the addition of another electron

D

oxygen is more electronegative

Text Solution

Verified by Experts

The correct Answer is:
C
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The formation of the oxide ion O_(g)^(2-) requires first an exothermic and then an endothermic step as shown below: O_(g)+e^(-) rarr O_(g)^(-) , DeltaH=-142 kJ mol^(-1) O(g)+e rarr O_(g)^(2-) , DeltaH=844kJ mol^(-1) This is because:

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The formation of water from H_(2)(g) and O_(2)(g) is an exothermic process because :

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