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In which of the following arrangements, ...

In which of the following arrangements, the order is not correct according to the property indicated against it?

A

Increasing size: `Al^(3+) lt Mg^(2+) lt Na^(+) lt F^(-)`

B

Increasing I.`E_(1)`: `B lt C lt N lt O`

C

Increasing `E.A_(1):I lt Br lt F lt Cl`

D

Increasing metallic radius : `Li lt Na lt K lt Rb`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which arrangement is not correct according to the indicated property, we will analyze each option step by step. ### Step 1: Analyze Increasing Size - **Elements**: Aluminum (Al), Magnesium (Mg), Potassium (K), Fluorine ion (F⁻) - **Analysis**: - All these elements have the same number of electrons (10) when considering their ionic forms. - The effective nuclear charge increases with the number of protons: - Al (13 protons) < Mg (12 protons) < K (19 protons) < F⁻ (9 protons). - Thus, the order of increasing size is correct as the effective nuclear charge increases, leading to a smaller size. ### Step 2: Analyze First Ionization Energy - **Elements**: Boron (B), Carbon (C), Nitrogen (N), Oxygen (O) - **Analysis**: - The electronic configurations are: - B: 1s² 2s² 2p¹ - C: 1s² 2s² 2p² - N: 1s² 2s² 2p³ (half-filled, more stable) - O: 1s² 2s² 2p⁴ - Nitrogen has a half-filled p subshell, which makes it more stable and requires more energy to remove an electron compared to oxygen. - Therefore, the correct order of increasing first ionization energy should be: B < C < O < N. - This means the given order is incorrect. ### Step 3: Analyze First Electron Affinity - **Elements**: Iodine (I), Bromine (Br), Fluorine (F), Chlorine (Cl) - **Analysis**: - Generally, electron affinity increases across a period and decreases down a group. - However, fluorine has a lower electron affinity than chlorine due to inter-electronic repulsion in its small size. - The correct order of increasing electron affinity should be: I < Br < Cl < F. - Thus, the given order is correct. ### Step 4: Analyze Increasing Metallic Radius - **Elements**: Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb) - **Analysis**: - As we move down the group, the metallic radius increases due to the addition of electron shells. - The correct order of increasing metallic radius is: Li < Na < K < Rb. - Therefore, this order is also correct. ### Conclusion - The only incorrect arrangement is for the first ionization energy: **Boron < Carbon < Nitrogen < Oxygen** is the correct order, but the question suggests it is in the wrong order. Thus, the answer is **B**.
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