Aqueous solutions of two compounds `M_(1)-O-H and M_(2)-O-H` are prepared in two different beakers. If, the electronegativity of `M_(1)=3.4,M_(2)=1.2, O=3.5 and H=2.1`, then the nature of two solutions will be respectively:

Options

A. acidic, basic
B. acidic, acidic
C. basic, acidic
D. basic, basic

Explanation

To determine the nature of the aqueous solutions of the compounds \( M_1OH \) and \( M_2OH \), we will analyze the electronegativity values of the elements involved and the resulting bond polarities.

### Step-by-Step Solution:

1. **Identify the Electronegativity Values:**
- Given values:
- Electronegativity of \( M_1 = 3.4 \)
- Electronegativity of \( M_2 = 1.2 \)
- Electronegativity of \( O = 3.5 \)
- Electronegativity of \( H = 2.1 \)

2. **Calculate the Electronegativity Differences:**
- For \( M_1OH \):
- Difference between \( M_1 \) and \( O \):
\[ |3.4 - 3.5| = 0.1 \]
- Difference between \( O \) and \( H \):
\[ |3.5 - 2.1| = 1.4 \]

- For \( M_2OH \):
- Difference between \( M_2 \) and \( O \):
\[ |1.2 - 3.5| = 2.3 \]
- Difference between \( O \) and \( H \):
\[ |3.5 - 2.1| = 1.4 \]

3. **Analyze the Bond Polarities:**
- For \( M_1OH \):
- The bond \( M_1-O \) has a small electronegativity difference (0.1), indicating a covalent bond.
- The bond \( O-H \) has a larger electronegativity difference (1.4), indicating a polar covalent bond.
- Since \( O \) is more electronegative than \( H \), it will attract the shared electrons more, leading to the release of \( H^+ \) ions in solution. Thus, \( M_1OH \) will be **acidic**.

- For \( M_2OH \):
- The bond \( M_2-O \) has a large electronegativity difference (2.3), indicating a highly polar bond, likely ionic.
- The bond \( O-H \) remains the same with a difference of 1.4.
- The high electronegativity difference suggests that the \( M_2-O \) bond will break, leading to the release of \( OH^- \) ions in solution. Thus, \( M_2OH \) will be **basic**.

4. **Conclusion:**
- The nature of the two solutions is:
- \( M_1OH \) is **acidic**.
- \( M_2OH \) is **basic**.

### Final Answer:
The nature of the two solutions will be respectively: **acidic** for \( M_1OH \) and **basic** for \( M_2OH \).

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