Consider the following values of I.E.(eV) for elements W and X:
`{:("Element",I.E_(1),I.E_(2),I.E_(3),I.E_(4)),(W,10.5,15.5,24.9,79.8),(X,8,14.8,78.9,105.8):}`
Other two element Y and Z hav outer electronic configuration `ns^(2)np^(4) and ns^(2)np^(5)` respectively. then according to given information which of the following compound(s) is/are not possible?

Options

A. `W_(2)Y_(3)`
B. `X_(2)Y_(3)`
C. `WZ_(2)`
D. `XZ_(2)`

Answer

To solve the problem, we need to analyze the ionization energies of elements W and X and determine their possible oxidation states. We will then evaluate the compounds that can be formed with elements Y and Z based on their outer electronic configurations.

### Step 1: Analyze Ionization Energies
We have the following ionization energies (I.E.) for elements W and X:

- **Element W**:
- I.E.1 = 10.5 eV
- I.E.2 = 15.5 eV
- I.E.3 = 24.9 eV
- I.E.4 = 79.8 eV

- **Element X**:
- I.E.1 = 8 eV
- I.E.2 = 14.8 eV
- I.E.3 = 78.9 eV
- I.E.4 = 105.8 eV

**Observation**:
- For W, there is a significant jump in ionization energy between I.E.3 and I.E.4, indicating that removing the fourth electron is much more difficult. Thus, W can easily lose 3 electrons, making its stable oxidation state +3.
- For X, there is a significant jump between I.E.2 and I.E.3, indicating that X can lose 2 electrons easily, making its stable oxidation state +2.

### Step 2: Determine Oxidation States of Y and Z
- Element Y has an outer electronic configuration of ns²np⁴, which means it can gain 2 electrons to achieve a stable noble gas configuration. Therefore, Y will typically have a valency of -2.
- Element Z has an outer electronic configuration of ns²np⁵, which means it can gain 1 electron to achieve a stable noble gas configuration. Therefore, Z will typically have a valency of -1.

### Step 3: Evaluate Possible Compounds
Now we will analyze the possible compounds formed by combinations of W, X, Y, and Z.

1. **Compound W₂Y₃**:
- W has a valency of +3, and Y has a valency of -2.
- The compound can be formed as W₂Y₃ (2 W for every 3 Y). **Possible**.

2. **Compound XY**:
- X has a valency of +2, and Y has a valency of -2.
- The compound can be formed as XY (1 X for every 1 Y). **Possible**.

3. **Compound WZ₂**:
- W has a valency of +3, and Z has a valency of -1.
- The compound would need to be WZ₃ to balance the charges (3 Z for every 1 W). **Not possible** as given is WZ₂.

4. **Compound XZ₂**:
- X has a valency of +2, and Z has a valency of -1.
- The compound can be formed as XZ₂ (1 X for every 2 Z). **Possible**.

### Conclusion
The compounds that are **not possible** are:
- WZ₂ (as it should be WZ₃)
- XY (as it can be formed)

Thus, the answer is that the compounds WZ₂ and XY are not possible.