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Electron affinity of the elements or ion...

Electron affinity of the elements or ions shown correctly?

A

`S gt O^(-)`

B

`P gt N^(-)`

C

`O^(-) gt S^(-)`

D

`N^(-) gt P`

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AI Generated Solution

The correct Answer is:
To determine the correct statements regarding the electron affinity of the elements or ions mentioned, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electron Affinity**: - Electron affinity is defined as the energy change that occurs when an electron is added to a neutral atom in the gas phase. A higher electron affinity indicates a greater ability to gain an electron. 2. **Comparing Sulfur (S) and Oxygen Ion (O⁻)**: - Sulfur (S) has a higher electron affinity than the oxygen ion (O⁻). This is because oxygen is smaller in size and already has a negative charge. Adding another electron to O⁻ (to form O²⁻) is endothermic (requires energy) due to electron-electron repulsion. In contrast, adding an electron to sulfur (to form S⁻) is exothermic (releases energy). **Conclusion**: Electron affinity of S > Electron affinity of O⁻. 3. **Comparing Phosphorus (P) and Nitrogen Ion (N⁻)**: - Phosphorus (P) has a higher electron affinity than the nitrogen ion (N⁻). Nitrogen is also small and already has a negative charge. Adding another electron to N⁻ (to form N²⁻) is unfavorable due to repulsion between the two negative charges. In contrast, phosphorus can easily gain an electron. **Conclusion**: Electron affinity of P > Electron affinity of N⁻. 4. **Comparing Oxygen Ion (O⁻) and Sulfur Ion (S⁻)**: - Between O⁻ and S⁻, even though both have negative charges, O⁻ is smaller and experiences greater repulsion when trying to gain another electron. Therefore, the electron affinity of O⁻ is less than that of S⁻. **Conclusion**: Electron affinity of O⁻ < Electron affinity of S⁻. 5. **Comparing Nitrogen Ion (N⁻) and Phosphorus (P)**: - This comparison is similar to the previous one. Since N⁻ has a negative charge and is small, it will repel an additional electron more than phosphorus would. Thus, phosphorus has a higher electron affinity. **Conclusion**: Electron affinity of P > Electron affinity of N⁻. ### Final Summary: - The correct statements regarding the electron affinities are: 1. Electron affinity of S > Electron affinity of O⁻. 2. Electron affinity of P > Electron affinity of N⁻. 3. Electron affinity of O⁻ < Electron affinity of S⁻. 4. Electron affinity of P > Electron affinity of N⁻.
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VK JAISWAL ENGLISH-PERIODIC PROPERTIES-ONE OR MORE ANSWERS IN/ARE CORRECT
  1. Correct order of electron affinity is/are:

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  2. Which of the following statement(s) is/are correct?

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  3. Electron affinity of the elements or ions shown correctly?

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  4. Which of the following statement regarding halogens is/are correct?

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  5. Which of the following statements are correct?

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  6. Consider the order O^(2-) lt F^(-) lt Na^(+) lt Mg^(2+). Then correct ...

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  7. Consider the following reaction: (i) O((g))+e^(-) to O((g))^(-),Delt...

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  8. Which of the following is incorrect order of property as indicated ?

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  9. Which of the following is/are correct order?

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  10. Consider the following sequence of reaction: If electronic config...

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  11. The correct statement is/are:

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  12. Which of the following statements is true about electronegativity?

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  13. Which of the following element have the similar value of electronegati...

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  14. Which of the following parameters cannot be estimated by using Born-Ha...

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  15. Select correct order(s) of electronegativity of element is/are:

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  16. Choose the correct statement(s):

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  17. Select equation having endothermic step:

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  18. Consider the following Born-Haber's cycle: (Where DeltaH(1),Delta...

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  19. Which of the followng oxides is/are amphoteric/

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  20. Which of the following show amphoteric behaviour?

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