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Consider the following Borh-Habber's cyc...

Consider the following Borh-Habber's cycle for formation of `MX_(3)(s)`.

Then calculate value `(q_(1))/(50)`, here `q_(1)` is electron affinity of X(g) in kJ/mol.

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The correct Answer is:
4
`-750=150+(3)/(2)xx200+350+q-1000`
`q=3xxDeltaH_(BG)=-550,`
`q_(1)=(550)/(3)=183,(q_(1))/(50)=3.66~~4.0`
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