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Which of the following is an example of ...

Which of the following is an example of super octet molecule ?

A

`ClF_(3)`

B

`PCl_(5)`

C

`IF_(7)`

D

All the three

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AI Generated Solution

The correct Answer is:
To determine which of the given molecules is an example of a super octet molecule, we need to analyze each option based on the number of electrons surrounding the central atom. A super octet molecule is defined as one that has more than 8 electrons around its central atom. Let's evaluate each option step by step. ### Step 1: Analyze ClF3 1. **Identify the central atom**: In ClF3, chlorine (Cl) is the central atom. 2. **Count valence electrons**: Chlorine has 7 valence electrons. 3. **Draw the Lewis structure**: Chlorine is bonded to 3 fluorine atoms. Each fluorine atom contributes 1 shared electron. 4. **Count shared electrons**: - Shared electrons from 3 fluorine atoms = 3. 5. **Total electrons around Cl**: - Valence electrons (7) + Shared electrons (3) = 10 electrons. 6. **Conclusion**: ClF3 has more than 8 electrons around the central atom, making it a super octet molecule. ### Step 2: Analyze PCl5 1. **Identify the central atom**: In PCl5, phosphorus (P) is the central atom. 2. **Count valence electrons**: Phosphorus has 5 valence electrons. 3. **Draw the Lewis structure**: Phosphorus is bonded to 5 chlorine atoms. 4. **Count shared electrons**: - Shared electrons from 5 chlorine atoms = 5. 5. **Total electrons around P**: - Valence electrons (5) + Shared electrons (5) = 10 electrons. 6. **Conclusion**: PCl5 also has more than 8 electrons around the central atom, making it a super octet molecule. ### Step 3: Analyze IF7 1. **Identify the central atom**: In IF7, iodine (I) is the central atom. 2. **Count valence electrons**: Iodine has 7 valence electrons. 3. **Draw the Lewis structure**: Iodine is bonded to 7 fluorine atoms. 4. **Count shared electrons**: - Shared electrons from 7 fluorine atoms = 7. 5. **Total electrons around I**: - Valence electrons (7) + Shared electrons (7) = 14 electrons. 6. **Conclusion**: IF7 has more than 8 electrons around the central atom, making it a super octet molecule. ### Final Conclusion All three molecules (ClF3, PCl5, and IF7) have more than 8 electrons around their central atoms. Therefore, the correct answer is: **Option 4: All the 3 are super octet molecules.** ---
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VK JAISWAL ENGLISH-CHEMICAL BONDING (BASIC)-SUBJECTIVE PROBLEMS
  1. Which of the following is an example of super octet molecule ?

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  2. Consider following compounds A to E : (A) XeF(n) " " (B) XeF((n+1)...

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  3. Consider the following five group (According to modern periodic table)...

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  4. Consider the following species and find out total number of species wh...

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  5. Consider the following table regarding interhalogen compounds, XY(n) (...

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  6. What is covalency of chlorine atom in second excited state ?

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  7. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  8. Calculate the value of X-Y, for XeOF(4). (X=Number of sigma bond pair ...

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  9. The molecule ABn is planar with six pairs of electrons around A in the...

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  10. Calculate value of (X+Y+Z)/(10), here X is O-N-O bond angle in NO(3)^(...

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  11. Calculate x+y+z for H(3)PO(3) acid, where x is no. of lone pairs, y is...

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  12. How many right angle, bond angles are present in TeF(5)^(-) molecular ...

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  13. How may possible angle FSeF bond angles are present in SeF(4) molecule...

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  14. In IF(6)^(-) and TeF(5)^(-), sum of axial d-orbitals which are used in...

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  15. Among the following, total no. of planar species is : (i) SF(4) " "...

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  16. Calculate the value of " x+y-z" here x,y and z are total number of non...

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  17. Consider the following table Then calculate value of "p+q+r-s-t".

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  18. In phosphorus acid, if X is number of non bonding electron pairs. Y is...

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  19. Calculate the number of p(pi)-d(pi) bond(s) present in SO(4)^(2-) :

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  20. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  21. Consider the following orbitals (i)3p(x) (ii)4d(z^(2)) (iii)3d(x^(2)...

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