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The molecule exhibiting maximum number o...

The molecule exhibiting maximum number of non-bonding electron pairs (l.p.) around the central atom is :

A

`XeOF_(4)`

B

`XeO_(2)F_(2)`

C

`XeF_(3)^(+)`

D

`XeO_(3)`

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The correct Answer is:
To determine which molecule exhibits the maximum number of non-bonding electron pairs (lone pairs) around the central atom, we will analyze the given options systematically. ### Step 1: Understand the concept of lone pairs Lone pairs are pairs of valence electrons that are not involved in bonding. They are important in determining the shape and reactivity of molecules. ### Step 2: Identify the central atom and its valence electrons We will look at the central atom in each molecule and count its valence electrons. The central atom is usually the atom that can form the most bonds or is the least electronegative. ### Step 3: Analyze each option 1. **Option A: Xenon (Xe)** - Valence electrons: 8 - Bonds formed: 5 (with 5 surrounding atoms) - Lone pairs: 1 (8 - 5 = 3, but only 1 is a lone pair since it forms 5 bonds) 2. **Option B: Xenon (Xe)** - Valence electrons: 8 - Bonds formed: 4 (with 4 surrounding atoms) - Lone pairs: 2 (8 - 4 = 4, but only 2 are lone pairs since it forms 4 bonds) 3. **Option C: Xenon trifluoride (XeF3+)** - Valence electrons: 8 - Bonds formed: 3 (with 3 fluorine atoms) - Lone pairs: 2 (8 - 3 = 5, but only 2 are lone pairs since it forms 3 bonds) 4. **Option D: Xenon trioxide (XeO3)** - Valence electrons: 8 - Bonds formed: 3 (with 3 oxygen atoms) - Lone pairs: 1 (8 - 3 = 5, but only 1 is a lone pair since it forms 3 bonds) ### Step 4: Compare the number of lone pairs Now, we compare the number of lone pairs in each option: - Option A: 1 lone pair - Option B: 2 lone pairs - Option C: 2 lone pairs - Option D: 1 lone pair ### Step 5: Conclusion The maximum number of lone pairs is found in Option B and Option C, both having 2 lone pairs. However, the question asks for the maximum number of non-bonding electron pairs around the central atom, and since both options have the same number, we can conclude that the molecule exhibiting the maximum number of non-bonding electron pairs is **XeF3+ (Option C)**. ### Final Answer: **The molecule exhibiting maximum number of non-bonding electron pairs around the central atom is XeF3+.**
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VK JAISWAL ENGLISH-CHEMICAL BONDING (BASIC)-SUBJECTIVE PROBLEMS
  1. The molecule exhibiting maximum number of non-bonding electron pairs (...

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  2. Consider following compounds A to E : (A) XeF(n) " " (B) XeF((n+1)...

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  3. Consider the following five group (According to modern periodic table)...

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  4. Consider the following species and find out total number of species wh...

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  5. Consider the following table regarding interhalogen compounds, XY(n) (...

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  6. What is covalency of chlorine atom in second excited state ?

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  7. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  8. Calculate the value of X-Y, for XeOF(4). (X=Number of sigma bond pair ...

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  9. The molecule ABn is planar with six pairs of electrons around A in the...

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  10. Calculate value of (X+Y+Z)/(10), here X is O-N-O bond angle in NO(3)^(...

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  11. Calculate x+y+z for H(3)PO(3) acid, where x is no. of lone pairs, y is...

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  12. How many right angle, bond angles are present in TeF(5)^(-) molecular ...

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  13. How may possible angle FSeF bond angles are present in SeF(4) molecule...

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  14. In IF(6)^(-) and TeF(5)^(-), sum of axial d-orbitals which are used in...

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  15. Among the following, total no. of planar species is : (i) SF(4) " "...

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  16. Calculate the value of " x+y-z" here x,y and z are total number of non...

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  17. Consider the following table Then calculate value of "p+q+r-s-t".

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  18. In phosphorus acid, if X is number of non bonding electron pairs. Y is...

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  19. Calculate the number of p(pi)-d(pi) bond(s) present in SO(4)^(2-) :

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  20. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  21. Consider the following orbitals (i)3p(x) (ii)4d(z^(2)) (iii)3d(x^(2)...

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