Home
Class 12
CHEMISTRY
In the Born-Haber cycle for the formatio...

In the Born-Haber cycle for the formation of solid common salt (NaCl), the largest contribution comes from :

A

the low ionization potential of Na

B

the high electron affinity of Cl

C

the low `DeltaH_("vap")` of Na(s)

D

the lattice energy

Text Solution

AI Generated Solution

The correct Answer is:
To determine the largest contribution in the Born-Haber cycle for the formation of solid common salt (NaCl), we need to analyze the options provided in the context of the Born-Haber cycle. ### Step-by-Step Solution: 1. **Understanding the Born-Haber Cycle**: The Born-Haber cycle is a thermodynamic cycle that relates the lattice energy of an ionic solid to the enthalpy changes involved in its formation. It includes steps such as sublimation, ionization, dissociation, electron affinity, and lattice formation. 2. **Analyzing the Options**: - **Option 1: Low ionization potential of Na**: The ionization energy of Na is +496 kJ/mol. While this value is significant, it is not the largest contribution in the cycle. - **Option 2: High electron affinity of Cl**: The electron affinity of Cl is -349 kJ/mol. This value indicates that energy is released when Cl gains an electron, but it is still not the largest contribution. - **Option 3: Low ΔH vaporization of Na**: The heat of vaporization of Na is +108 kJ/mol. This value is relatively low compared to the lattice energy and does not contribute significantly to the overall energy change. - **Option 4: Lattice energy**: The lattice energy (U) is -788 kJ/mol. This is the energy released when gaseous ions combine to form a solid ionic compound. It is a large negative value, indicating a strong attraction between the ions in the solid state. 3. **Conclusion**: Among all the contributions analyzed, the lattice energy has the largest magnitude and is the most significant contributor to the overall energy change in the formation of NaCl. Therefore, the correct answer is **Option 4: Lattice energy**. ### Final Answer: The largest contribution in the Born-Haber cycle for the formation of solid common salt (NaCl) comes from the **lattice energy**. ---
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise Level 3 (Passive 1)|6 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise Level 3 (Passive 2)|6 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|54 Videos
  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|64 Videos
  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise LEVEL 2|144 Videos

Similar Questions

Explore conceptually related problems

Born-Haber cycle is used to determine

Why common salt (NaCl) sometimes appear yellow?

Why common salt (NaCl) sometimes appear yellow?

Why common salt (NaCl) sometimes appear yellow?

What is Born-Haber cycle? Explain with an example.

During formation of urine NaCl is returned to the medullary interstitium from the

Common salt is obtained from sea water by

Give reasons for the following : In the laboratory preparation of HCl acid from NaCl and conc . H_(2)SO_(4) , the residual salt formed at temperatures above 200^(@)C forms a hard crust and sticks to the glass.

(a) In the formation of compound between two atoms A and B, A loses two electrons and B gains one electron. (i) What is the nature of bond between A and B? (ii) Suggest the formula of the compound formed between A and B. (b) On similar lines explain the formation of MgCl_(2) molecule. (c ) Common salt conducts electricity only in the molten state. Why? (d) Why is melting point of NaCl high ?

(i) Name the most common ore of the metal aluminum from which the metal is extracted. Write the chemical formula of the ore. (ii) Name the process by which impure ore of aluminum gets purified by using concentrated solution of an alkali. (iii) Write the equation for the formation of aluminum at the cathode during the electrolysis of alumina.

VK JAISWAL ENGLISH-CHEMICAL BONDING (BASIC)-Level 2
  1. Which of the following is incorrectly matched ?

    Text Solution

    |

  2. The ionic bond X^(+)Y^(-) are formed when : (I) electron affinity of...

    Text Solution

    |

  3. In the Born-Haber cycle for the formation of solid common salt (NaCl),...

    Text Solution

    |

  4. Species having maximum 'Cl-O' bond order is :

    Text Solution

    |

  5. Which of the following species contains minimum number of atoms in XY ...

    Text Solution

    |

  6. The molecule ML(x) is planar with 7 pairs of electrons around M in the...

    Text Solution

    |

  7. Choose the correct option for the collowing molecule in view of chemic...

    Text Solution

    |

  8. Which of the following statement is correct about I(3)^(+) and I(3)^(-...

    Text Solution

    |

  9. In which of the following molecular shape d(z^(2)) orbital must not be...

    Text Solution

    |

  10. The correct statement regarding SO(2) molecule is :

    Text Solution

    |

  11. A molecule XY(2) contains two sigma bonds two pi bond and one lone pai...

    Text Solution

    |

  12. In which of the following pairs, both the species have the same hybrid...

    Text Solution

    |

  13. Which of the following possess two lone pair of electrons on the centr...

    Text Solution

    |

  14. Select pair of compounds in which both have different hybridization bu...

    Text Solution

    |

  15. The species having no ppi-ppi bond but its bond order equal to that of...

    Text Solution

    |

  16. Which of the following fact is directly explained by the statement oxy...

    Text Solution

    |

  17. Which of the following compound has maximum "C-C" single bond length ?

    Text Solution

    |

  18. If two different non-axial d-orbitals having 'xz' nodal plane form pi-...

    Text Solution

    |

  19. Assuming pure 2s and 2p orbitals of carbon are used in forming CH(4) m...

    Text Solution

    |

  20. Which of the following is correct order of sigma - bond strength ? ...

    Text Solution

    |