To determine which statement is false according to the VSEPR model, we will analyze the given statements one by one based on the information provided in the video transcript.
### Step 1: Analyze the first statement about SbA4 and Sa4 being isostructural.
- **SbA4** (Antimony tetrafluoride) has a central atom of antimony (Sb) from group 15, which has 5 valence electrons. With 4 fluorine atoms (each contributing 1 electron) and one additional negative charge, the total number of electrons becomes 6.
- The structure can be drawn with 4 bond pairs and 1 lone pair, leading to a steric number of 5. This indicates sp³d hybridization and a trigonal bipyramidal geometry.
- **Sa4** (Sulfur tetrafluoride) has a central atom of sulfur (S) from group 16, which has 6 valence electrons. With 4 fluorine atoms, it also has 4 bond pairs and 1 lone pair, leading to a steric number of 5, sp³d hybridization, and trigonal bipyramidal geometry.
- Both species have the same geometry, hence they are isostructural. This statement is **true**.
### Step 2: Analyze the second statement about hybridization in IUF5.
- **IUF5** (Iodine pentafluoride) has iodine (I) as the central atom from group 17, which has 7 valence electrons. With 5 fluorine atoms and 1 oxygen, the total number of electrons is 6 bond pairs and 0 lone pairs.
- The steric number is 6, leading to sp³d² hybridization. This statement is also **true**.
### Step 3: Analyze the third statement regarding double bonds in SOF4 and XeO3F2.
- **SOF4** (Sulfur oxyfluoride) has sulfur as the central atom from group 16, with 6 valence electrons. It has 4 bond pairs and 1 lone pair, leading to a steric number of 5 and sp³d hybridization.
- **XeO3F2** (Xenon trifluoride) has xenon as the central atom from group 18, with 8 valence electrons. It has 3 oxygen atoms and 2 fluorine atoms, leading to a steric number of 5 and sp³d hybridization.
- The statement claims that double bonds in SOF4 and XeO3F2 occupy equatorial positions. However, SOF4 does not have double bonds; it has single bonds with one lone pair. Therefore, this statement is **false**.
### Conclusion
The false statement is about the double bonds in SOF4 and XeO3F2 occupying equatorial positions, as SOF4 does not contain double bonds.