If the central atom is of third row or below this in the periodic table, then lone pair will occupy a stereochemically inactive s-orbital and bonding will be through almost pure p-orbitals and bond angles are nearly `90^(@)`, if the substituent's electronegativity value is `le 2.5`.
The hybridisation of atomic orbitals of central atom "Xe" in `XeO_(4), XeO_(2)F_(2) and XeOF_(4)` respectively.

Options

A. `sp^(3),sp^(3)d^(2),sp^(3)d^(2)`
B. `sp^(3)d,sp^(3)d,sp^(3)d^(2)`
C. `sp^(3),sp^(3)d^(2),sp^(3)d`
D. `sp^(3),sp^(3)d,sp^(3)d^(2)`

Answer

To determine the hybridization of the central atom "Xe" in the compounds XeO4, XeO2F2, and XeOF4, we will follow these steps:

### Step 1: Identify the Valence Electrons of Xenon
Xenon (Xe) is a noble gas located in Group 18 of the periodic table. It has a total of 8 valence electrons.

### Step 2: Analyze the Molecular Structures
1. **For XeO4**:
- Xenon is bonded to four oxygen atoms.
- Each oxygen forms a double bond with xenon.
- There are no lone pairs on xenon.
- **Bond pairs**: 4 (from the four double bonds).
- **Lone pairs**: 0.
- **Steric number** = Bond pairs + Lone pairs = 4 + 0 = 4.
- **Hybridization**: The hybridization corresponding to a steric number of 4 is **sp³**.

2. **For XeO2F2**:
- Xenon is bonded to two oxygen atoms and two fluorine atoms.
- Each oxygen forms a double bond with xenon, and each fluorine forms a single bond.
- There is one lone pair on xenon.
- **Bond pairs**: 4 (2 from double bonds with oxygen and 2 from single bonds with fluorine).
- **Lone pairs**: 1.
- **Steric number** = Bond pairs + Lone pairs = 4 + 1 = 5.
- **Hybridization**: The hybridization corresponding to a steric number of 5 is **sp³d**.

3. **For XeOF4**:
- Xenon is bonded to one oxygen atom and four fluorine atoms.
- The oxygen forms a double bond with xenon, and each fluorine forms a single bond.
- There is one lone pair on xenon.
- **Bond pairs**: 5 (1 from the double bond with oxygen and 4 from single bonds with fluorine).
- **Lone pairs**: 1.
- **Steric number** = Bond pairs + Lone pairs = 5 + 1 = 6.
- **Hybridization**: The hybridization corresponding to a steric number of 6 is **sp³d²**.

### Summary of Hybridizations:
- **XeO4**: sp³
- **XeO2F2**: sp³d
- **XeOF4**: sp³d²