Consider following compounds A to E :
(A) `XeF_(n) " " (B) XeF_((n+1))^(+) " " (C ) XeF_((n+1))^(-) " " (D) XeF_((n+2))`
(E ) `XeF_((n+4))^(2-)`,
If value of n is 4, then calculate value of `p div q` here, 'p' is total number of bond pair and 'q' is total number of lone pair on central atoms of compounds (A) to (E ).

Explanation

To solve the problem, we need to determine the total number of bond pairs (p) and lone pairs (q) on the central atom (xenon) for the given compounds A to E, where n = 4.

### Step-by-Step Solution:

1. **Identify the Compounds:**
- (A) `XeF4`
- (B) `XeF5^+`
- (C) `XeF5^-`
- (D) `XeF6`
- (E) `XeF8^2-`

2. **Determine the Number of Bond Pairs and Lone Pairs for Each Compound:**

**Compound A: `XeF4`**
- Xenon (Xe) has 8 valence electrons.
- 4 electrons are used to form bonds with 4 fluorine atoms.
- Remaining electrons = 8 - 4 = 4 electrons (which form 2 lone pairs).
- **Bond pairs (p) = 4, Lone pairs (q) = 2.**

**Compound B: `XeF5^+`**
- The positive charge means we have one less electron.
- Total electrons = 8 - 1 = 7.
- 5 electrons are used to form bonds with 5 fluorine atoms.
- Remaining electrons = 7 - 5 = 2 electrons (which form 1 lone pair).
- **Bond pairs (p) = 5, Lone pairs (q) = 1.**

**Compound C: `XeF5^-`**
- The negative charge means we have one extra electron.
- Total electrons = 8 + 1 = 9.
- 5 electrons are used to form bonds with 5 fluorine atoms.
- Remaining electrons = 9 - 5 = 4 electrons (which form 2 lone pairs).
- **Bond pairs (p) = 5, Lone pairs (q) = 2.**

**Compound D: `XeF6`**
- Total electrons = 8 (no charge).
- 6 electrons are used to form bonds with 6 fluorine atoms.
- Remaining electrons = 8 - 6 = 2 electrons (which form 1 lone pair).
- **Bond pairs (p) = 6, Lone pairs (q) = 1.**

**Compound E: `XeF8^2-`**
- The negative charge means we have two extra electrons.
- Total electrons = 8 + 2 = 10.
- 8 electrons are used to form bonds with 8 fluorine atoms.
- Remaining electrons = 10 - 8 = 2 electrons (which form 1 lone pair).
- **Bond pairs (p) = 8, Lone pairs (q) = 1.**

3. **Calculate Total p and q:**
- Total bond pairs (p) = 4 (A) + 5 (B) + 5 (C) + 6 (D) + 8 (E) = 28.
- Total lone pairs (q) = 2 (A) + 1 (B) + 2 (C) + 1 (D) + 1 (E) = 7.

4. **Calculate p/q:**
- p/q = 28 / 7 = 4.

### Final Answer:
The value of `p/q` is **4**.