Calculate value of `(X+Y+Z)/(10)`, here X is O-N-O bond angle in `NO_(3)^(-)` Y is O-N-O bond angle in `NO_(2)^(+)` and Z is F-Xe-F adjacent bond angle in `XeF_(4)`.

Explanation

To solve the problem, we need to calculate the values of X, Y, and Z based on the bond angles in the given compounds, and then find the value of \((X + Y + Z) / 10\).

### Step 1: Determine the bond angle X in \(NO_3^-\)
- The structure of the nitrate ion (\(NO_3^-\)) is trigonal planar due to resonance, with nitrogen at the center and three oxygen atoms surrounding it.
- The bond angle between the oxygen atoms (O-N-O) in \(NO_3^-\) is \(120^\circ\).
- Therefore, \(X = 120^\circ\).

### Step 2: Determine the bond angle Y in \(NO_2^+\)
- The structure of the nitronium ion (\(NO_2^+\)) is linear, with nitrogen at the center and two oxygen atoms.
- The bond angle between the oxygen atoms (O-N-O) in \(NO_2^+\) is \(180^\circ\).
- Therefore, \(Y = 180^\circ\).

### Step 3: Determine the bond angle Z in \(XeF_4\)
- The structure of xenon tetrafluoride (\(XeF_4\)) is square planar, with xenon at the center and four fluorine atoms surrounding it.
- The adjacent bond angle between the fluorine atoms (F-Xe-F) is \(90^\circ\).
- Therefore, \(Z = 90^\circ\).

### Step 4: Sum the values of X, Y, and Z
- Now we can sum the values:
\[ X + Y + Z = 120^\circ + 180^\circ + 90^\circ = 390^\circ \]

### Step 5: Calculate \((X + Y + Z) / 10\)
- Finally, we divide the sum by 10:
\[ \frac{X + Y + Z}{10} = \frac{390^\circ}{10} = 39 \]

### Final Answer
Thus, the value of \((X + Y + Z) / 10\) is \(39\).

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