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In IF(6)^(-) and TeF(5)^(-), sum of axia...

In `IF_(6)^(-) and TeF_(5)^(-)`, sum of axial d-orbitals which are used in hybridisation in both species.

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To solve the problem of finding the sum of axial d-orbitals used in hybridization for the species \( IF_6^- \) and \( TeF_5^- \), we will follow these steps: ### Step 1: Determine the hybridization of \( IF_6^- \) 1. **Identify the central atom**: The central atom in \( IF_6^- \) is iodine (I). 2. **Count the valence electrons**: Iodine has 7 valence electrons (Group 17). The negative charge adds 1 more electron, giving a total of 8 valence electrons. 3. **Count the bonding pairs**: There are 6 fluorine atoms bonded to iodine, contributing 6 bonding pairs. 4. **Count the lone pairs**: With 8 total electrons and 6 bonding pairs, there is 1 lone pair left. 5. **Calculate the steric number**: The steric number is the sum of bonding pairs and lone pairs, which is \( 6 + 1 = 7 \). 6. **Determine hybridization**: A steric number of 7 corresponds to \( sp^3d^3 \) hybridization. ### Step 2: Identify the d-orbitals used in \( IF_6^- \) 1. The d-orbitals involved in \( sp^3d^3 \) hybridization are: - \( d_{xy} \) - \( d_{x^2-y^2} \) - \( d_{z^2} \) ### Step 3: Determine the hybridization of \( TeF_5^- \) 1. **Identify the central atom**: The central atom in \( TeF_5^- \) is tellurium (Te). 2. **Count the valence electrons**: Tellurium has 6 valence electrons (Group 16). The negative charge adds 1 more electron, giving a total of 7 valence electrons. 3. **Count the bonding pairs**: There are 5 fluorine atoms bonded to tellurium, contributing 5 bonding pairs. 4. **Count the lone pairs**: With 7 total electrons and 5 bonding pairs, there are 1 lone pair left. 5. **Calculate the steric number**: The steric number is \( 5 + 1 = 6 \). 6. **Determine hybridization**: A steric number of 6 corresponds to \( sp^3d^2 \) hybridization. ### Step 4: Identify the d-orbitals used in \( TeF_5^- \) 1. The d-orbitals involved in \( sp^3d^2 \) hybridization are: - \( d_{x^2-y^2} \) - \( d_{z^2} \) ### Step 5: Sum the axial d-orbitals used in both species 1. **Axial d-orbitals in \( IF_6^- \)**: - \( d_{x^2-y^2} \) and \( d_{z^2} \) (2 axial d-orbitals). 2. **Axial d-orbitals in \( TeF_5^- \)**: - \( d_{x^2-y^2} \) and \( d_{z^2} \) (2 axial d-orbitals). 3. **Total axial d-orbitals**: \( 2 + 2 = 4 \). ### Final Answer The sum of axial d-orbitals used in hybridization in both species \( IF_6^- \) and \( TeF_5^- \) is **4**. ---
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