Consider the following species `NO_(3)^(-), SO_(4)^(2-), ClO_(3)^(-),SO_(3), PO_(4)^(3-), XeO_(3),CO_(3)^(2-), SO_(3)^(2-)`
Then calculate value of |x-y|, where
x : Total number of species which have bond order 1.5 or greater than 1.5
y : Total number of species which have bond order less than 1.5

Explanation

To solve the problem, we need to calculate the bond order of each species listed and then determine how many of these species have a bond order of 1.5 or greater (denoted as x) and how many have a bond order less than 1.5 (denoted as y). Finally, we will calculate the absolute difference |x - y|.

### Step 1: Determine the bond order for each species

1. **NO₃⁻ (Nitrate Ion)**:
- Structure: Resonance with one double bond and two single bonds.
- Bond Order Calculation:
\[ \text{Bond Order} = \frac{\text{Number of Bonds}}{\text{Number of Bonding Pairs}} = \frac{2 + 1}{3} = 1.33 \]

2. **SO₄²⁻ (Sulfate Ion)**:
- Structure: Resonance with two double bonds and two single bonds.
- Bond Order Calculation:
\[ \text{Bond Order} = \frac{4}{4} = 1.5 \]

3. **ClO₃⁻ (Chlorate Ion)**:
- Structure: Resonance with one double bond and two single bonds.
- Bond Order Calculation:
\[ \text{Bond Order} = \frac{2 + 1}{3} = 1.66 \]

4. **SO₃ (Sulfur Trioxide)**:
- Structure: One double bond with each of the three oxygen atoms.
- Bond Order Calculation:
\[ \text{Bond Order} = 2 \]

5. **PO₄³⁻ (Phosphate Ion)**:
- Structure: Resonance with one double bond and three single bonds.
- Bond Order Calculation:
\[ \text{Bond Order} = \frac{1 + 3}{4} = 1.25 \]

6. **XeO₃ (Xenon Trioxide)**:
- Structure: One double bond with each of the three oxygen atoms.
- Bond Order Calculation:
\[ \text{Bond Order} = 2 \]

7. **CO₃²⁻ (Carbonate Ion)**:
- Structure: Resonance with one double bond and two single bonds.
- Bond Order Calculation:
\[ \text{Bond Order} = \frac{2 + 1}{3} = 1.33 \]

8. **SO₃²⁻ (Sulfite Ion)**:
- Structure: Resonance with one double bond and two single bonds.
- Bond Order Calculation:
\[ \text{Bond Order} = \frac{2 + 1}{3} = 1.33 \]

### Step 2: Count the number of species with bond orders

- **Species with bond order ≥ 1.5 (x)**:
- SO₄²⁻ (1.5)
- ClO₃⁻ (1.66)
- SO₃ (2)
- XeO₃ (2)

Total: **4 species** (x = 4)

- **Species with bond order < 1.5 (y)**:
- NO₃⁻ (1.33)
- PO₄³⁻ (1.25)
- CO₃²⁻ (1.33)
- SO₃²⁻ (1.33)

Total: **4 species** (y = 4)

### Step 3: Calculate |x - y|

\[ |x - y| = |4 - 4| = 0 \]

### Final Answer
The value of |x - y| is **0**.

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