Home
Class 12
CHEMISTRY
Nodal planes of pi-bonds in CH(2)=C=C=CH...

Nodal planes of `pi`-bonds in `CH_(2)=C=C=CH_(2)` are located in,

A

All are in molecular plane

B

Two in molecular plane and one in a plane perpendicular to molecular plane which contains C-C sigma-bond

C

On is molecular plane and two in plane perpendicular to molecular plane which contains C-C sigma-bonds

D

Two in molecular plane and one in a perpendicular to molecular plane which bisects C-C sigma-bonds at right angle.

Text Solution

AI Generated Solution

The correct Answer is:
To determine the nodal planes of the π-bonds in the compound CH₂=C=C=CH₂, we need to analyze the structure and bonding of the molecule step by step. ### Step 1: Draw the Structure of the Molecule The first step is to visualize the structure of the molecule. CH₂=C=C=CH₂ consists of two terminal carbon atoms (each bonded to two hydrogen atoms) and two central carbon atoms that are double-bonded to each other. **Hint:** Start by sketching the molecule to understand its geometry and bonding. ### Step 2: Identify the Types of Bonds In the structure, we have: - Sigma (σ) bonds: These are single bonds formed by the head-on overlap of atomic orbitals. In this case, the C-H and C=C bonds are σ bonds. - Pi (π) bonds: These are formed by the side-to-side overlap of p orbitals. The double bonds between the central carbons (C=C) consist of one σ bond and one π bond. **Hint:** Remember that each double bond consists of one σ bond and one π bond. ### Step 3: Determine the Nodal Planes of the π-bonds For π-bonds, the nodal planes are the planes where the probability of finding an electron is zero. In the case of the π-bonds in the molecule: - The π-bond between the first and second carbon (C1=C2) has a nodal plane that is perpendicular to the plane of the molecule. - The π-bond between the second and third carbon (C2=C3) also has a nodal plane that is perpendicular to the plane of the molecule. **Hint:** Nodal planes for π-bonds are typically perpendicular to the bond axis. ### Step 4: Identify the Orientation of the Nodal Planes The nodal planes of the π-bonds are located: 1. One nodal plane between the first and second carbons (C1=C2). 2. Another nodal plane between the second and third carbons (C2=C3). These nodal planes are oriented in such a way that they are perpendicular to the plane of the molecule, which contains the σ-bonds. **Hint:** Visualize the orientation of the bonds and how the nodal planes relate to them. ### Conclusion In summary, the nodal planes of the π-bonds in CH₂=C=C=CH₂ are located in planes that are perpendicular to the molecular plane containing the σ-bonds. **Final Answer:** The nodal planes of the π-bonds in CH₂=C=C=CH₂ are located in planes perpendicular to the molecular plane containing the σ-bonds.

To determine the nodal planes of the π-bonds in the compound CH₂=C=C=CH₂, we need to analyze the structure and bonding of the molecule step by step. ### Step 1: Draw the Structure of the Molecule The first step is to visualize the structure of the molecule. CH₂=C=C=CH₂ consists of two terminal carbon atoms (each bonded to two hydrogen atoms) and two central carbon atoms that are double-bonded to each other. **Hint:** Start by sketching the molecule to understand its geometry and bonding. ### Step 2: Identify the Types of Bonds ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise Level 3|77 Videos
  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise ONE OR MORE ANSWER IS/ARE CORRECT|78 Videos
  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|64 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|54 Videos

Similar Questions

Explore conceptually related problems

How many sigma bonds and pi bonds are present in CH_(2)=C=CH_(2) ?

The structure of CH_(2)=C=CH_(2) is :

Number of bonds in given compound is: CH_(2)=C=CH-C=CH

Indicate the sigma & pi bonds in (i) CH_(2)Cl_(2) (ii) CH_(3)-C-=C-CH_(3)

Calculate the number of sigma,pi and non-bonding (i.e lone pair) electrons in the following compounds (a) H_(2) C =CH -CH=CH_(2) (b) H_(3)C - C -= C -CH = CH -CH_(3) (c) H_(3)C-underset(CH_(3))underset(|)CH-overset(O)overset(||)C -C -= C -CH =CH - C-=N

In the compound CH_(2)=CH-CH_(2)-CH_(2)-C-=CH the C_(2)-C_(3) bond is of

In the organic compound CH_(2)=CH-CH_(2)-CH_(2)-C equiv CH , the CH-CH_(2) bond is formed by the interaction of a pair of hybridised orbitals :

Calculate enthalpy change of the following reaction : CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3) - CH_(3)(g) The bond energy of C - H, C - C, C = C, H - H are 414,347, 615 and 436 kJ mol^(-1) respectively.

In the organic compound CH_(2) = CH – CH_(2) – CH_(2) – C equivCH , the pair of hydridised orbitals involved in the formation of: C_(2) – C_(3) bond is: (a) sp – sp_(2) (b) sp – sp_(3) (c) sp_(2 )– sp_(3) (d) sp_(3) – sp_(3)

IUPAC name of the following is CH_(2) = C - CH_(2)-CH_(2) - C -= CH

VK JAISWAL ENGLISH-CHEMICAL BONDING (ADVANCED)-Level 2
  1. Which among the followiing molecules is not perfect flat?

    Text Solution

    |

  2. Which of the following structure(s) is /are non-planar?

    Text Solution

    |

  3. Nodal planes of pi-bonds in CH(2)=C=C=CH(2) are located in,

    Text Solution

    |

  4. Which of the following have X-O-X linkage ? (where X is central atom...

    Text Solution

    |

  5. Select the correct statements:

    Text Solution

    |

  6. Oxidation state of 'S' in peroxodisulphuric acid and sodium tetrathion...

    Text Solution

    |

  7. Structure of Na(2)[B(4)O(5)(OH)(4)]*8H(2)O contains

    Text Solution

    |

  8. Which of the following molecular species is not linear?

    Text Solution

    |

  9. Incorrect match is :

    Text Solution

    |

  10. Consider the following reactions: MX(4)+X'(2) to MX(4)X(2)' If ato...

    Text Solution

    |

  11. Select the correct statements:

    Text Solution

    |

  12. In which of the following species, d-obitals having xz an yz two nodal...

    Text Solution

    |

  13. The correct order of increasing s-character (in percentage) in the hyb...

    Text Solution

    |

  14. The shapes of MnO(4)^(-) ion and the hybridization of Mn in MnO(4)^(-)...

    Text Solution

    |

  15. Which one of the following molecule will have all equal X-F bonds leng...

    Text Solution

    |

  16. Consider the following information (F=F or Cl) According to given...

    Text Solution

    |

  17. In which of the following cases C-C bond length will be highest?

    Text Solution

    |

  18. In which of the following cases C-C bond length will be highest? (I)...

    Text Solution

    |

  19. The correct order of equatorial FSF bond angle in the folllowing compo...

    Text Solution

    |

  20. Incorrect orders of bond angle is :

    Text Solution

    |