Which one is correct for bond angle?

Options

A. `PF_(3)gtPCl_(3)`
B. `OCl_(2)=ClO_(2)`
C. `NF_(3)gtNH_(3)`
D. `PCl_(3)gtPF_(3)`

Answer

To determine the correct bond angle among the given options, we need to analyze the bond angles in different molecules based on the electronegativity of the central atom and the surrounding atoms.

### Step-by-Step Solution:

1. **Understanding Bond Angles**:
- Bond angles are influenced by the electronegativity of the atoms involved. The bond angle is directly proportional to the electronegativity of the central atom and inversely proportional to the electronegativity of the surrounding atoms.

2. **Analyzing PF3**:
- In PF3, phosphorus (P) is the central atom, and fluorine (F) is more electronegative than phosphorus. The bond angle will be less due to the high electronegativity of fluorine, which pulls the bonding electrons closer to itself, reducing the bond angle.

3. **Analyzing PCl3**:
- In PCl3, chlorine (Cl) is less electronegative than fluorine. Therefore, the bond angle in PCl3 will be larger than in PF3 because chlorine's lower electronegativity allows the bond angle to increase due to less electron withdrawal.

4. **Analyzing OCl2**:
- In OCl2, oxygen (O) has lone pairs which can affect the bond angle. The presence of lone pairs tends to compress the bond angle. Additionally, chlorine's electronegativity is lower than that of oxygen, which can also lead to a decrease in the bond angle due to back-bonding.

5. **Analyzing NF3**:
- In NF3, nitrogen (N) is the central atom, and fluorine is highly electronegative. The bond angle in NF3 will be less than that of ammonia (NH3) because the high electronegativity of fluorine pulls the bonding electrons closer, reducing the bond angle.

6. **Conclusion**:
- Comparing the bond angles of PF3, PCl3, OCl2, and NF3, we find that PCl3 has the largest bond angle due to the lower electronegativity of chlorine compared to fluorine. Therefore, the correct answer is that the bond angle in PCl3 is greater than that in PF3, NF3, and OCl2.

### Final Answer:
The correct statement regarding bond angles is that the bond angle in PCl3 is greater than in PF3, NF3, and OCl2.

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