If P to T are second period p-block elements then which of the following graph show corrrect relation between valence electrons in `P_(2) to T_(2)`

Options

A.
B.
C.
D.

Explanation

To solve the problem, we will analyze the relationship between the number of valence electrons in the second period p-block elements (B, C, N, O, F, Ne) and their corresponding bond orders.

### Step-by-Step Solution:

1. **Identify the Second Period p-Block Elements:**
The second period p-block elements are:
- Boron (B)
- Carbon (C)
- Nitrogen (N)
- Oxygen (O)
- Fluorine (F)
- Neon (Ne)

2. **Determine the Number of Valence Electrons:**
Each of these elements has the following number of valence electrons:
- Boron (B): 3 valence electrons
- Carbon (C): 4 valence electrons
- Nitrogen (N): 5 valence electrons
- Oxygen (O): 6 valence electrons
- Fluorine (F): 7 valence electrons
- Neon (Ne): 8 valence electrons

3. **Determine the Bond Order for Diatomic Molecules:**
The bond orders for the diatomic molecules formed by these elements are:
- B₂: Bond order = 1
- C₂: Bond order = 2
- N₂: Bond order = 3
- O₂: Bond order = 2
- F₂: Bond order = 1
- Ne₂: Bond order = 0 (Noble gas, no bond)

4. **Plot the Relationship:**
Now, we can plot the relationship between the number of valence electrons and bond order:
- For 3 valence electrons (B): Bond order = 1
- For 4 valence electrons (C): Bond order = 2
- For 5 valence electrons (N): Bond order = 3
- For 6 valence electrons (O): Bond order = 2
- For 7 valence electrons (F): Bond order = 1
- For 8 valence electrons (Ne): Bond order = 0

5. **Analyze the Graph:**
From the data, we see that as we move from Boron to Nitrogen, the bond order increases, reaching a maximum at Nitrogen. After that, as we move to Oxygen and Fluorine, the bond order decreases. This indicates a peak in bond order at Nitrogen.

6. **Select the Correct Graph:**
The correct graph will show an initial increase in bond order as the number of valence electrons increases, followed by a decrease after reaching the peak at Nitrogen. Therefore, the correct option is the one that illustrates this trend.

### Conclusion:
The correct answer is option number one, which shows the bond order first increasing and then decreasing as the number of valence electrons increases from B to Ne.