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Ammonia forms the complex [Cu(NH(3))(4)]...

Ammonia forms the complex `[Cu(NH_(3))_(4)]^(2+)` will copper ions in alkaline solution but not in acidic solution. The reason for this is

A

In alkline solution `Cu(OH)_(2)` is precipitated which is soluble in exces of alkali

B

Copper hydroxide is amphoteric substance

C

in acidic solution hydration protects `Cu^(2+)` ions.

D

In acidic solution protons are coordinated with ammonia molecules forming `NH_(4)+^(+)` ion.

Text Solution

Verified by Experts

The correct Answer is:
D

`Cu^(2+)(aq)+4NH_(3)overset(OH^(-)) hArr [Cu(NH_(3))_(4)]^(2+)`
`Cu^(2+)(aq)+4NH_(3) overset(OH^(+))hArr Cu^(2+)+4NH_(4)^(+)` (No complex formation)
As `NH_(3)` combines with `H^(+)` of acid and changes to `NH_(4)^(+)` which have no donor site.
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