MnO(4)^(-) is of intense pink colour, th...

`MnO_(4)^(-)` is of intense pink colour, though Mn is in (+7) oxidation state, it is due to:

oxygen gives colour to it

Charge transfer when Mn(+7) gives its electron to oxygen and oxidise to Mn (+8) temporarily

Charge transfer when oxygen gives its electron to Mn(+7) changing in Mn(+6)

none is correct explanation

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Transition metals usually from coloured complexes and d-d transitions (t_(2g)hArre_(g)) are responsible for colour as the energy difference between t_(2g) and e_(g) lies in visible region. But all the coloured ions are not dut to d-d transition but charge transfer bands also play important roles. Charge transfer bands may be of two types. (i) ligand to metal (CTLM) " "(ii) metal to ligand (CTML). Charge transfer transition always produces intense colour as compared to d-d transition. MnO_(4)^(-) is dark purple coloured though Mn is in (+VII) oxidation state with 3d^(@) configuration

The compound in which Mn has oxidation state of +3 is

With F highest stable oxidation state of Mn is

With O highest possible oxidation state of Mn is

The pink colour of phenolphthalein in alkaline medium is due to

The stable oxidation states of Mn are

Assertion : Solution of Na_(2) CrO_(4) in water is intensely coloured Reason : Oxidation state of Cr in Na_(2) CrO_(4) is + VI .

On oxidation of S_(2)O_(3)^(2-) by MnO_(4)^(-) in neutral aqueous medium, the oxidation state of S would change from :

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