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Which of the following statement is not ...

Which of the following statement is not true for the reaction given below:
`[Cu(H_(2)O)_(4)]^(2+)+ 4NH_(4) hArr [Cu(NH_(3))_(4)]^(2+)+4H_(2)O`

A

It is ligand substitution reaction

B

`NH_(3)` is a relatively strong field ligand while `H_(2)O` is a weak field ligand

C

During the reaction, there is a change in colour from light blue to dark blue

D

`[Cu(NH_(3))_(4)]^(2+)`, has a tetrahedral structure and is paramagnetic

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The correct Answer is:
To determine which statement is not true for the given reaction: \[ [Cu(H_2O)_4]^{2+} + 4NH_3 \rightleftharpoons [Cu(NH_3)_4]^{2+} + 4H_2O \] we will analyze each statement provided. ### Step-by-Step Solution: 1. **Identify the Reaction Type**: - The reaction involves the substitution of ligands in the complex ion. The water ligands in \([Cu(H_2O)_4]^{2+}\) are replaced by ammonia ligands to form \([Cu(NH_3)_4]^{2+}\). - **Conclusion**: This is a ligand substitution reaction. 2. **Evaluate the Strength of Ligands**: - According to Crystal Field Theory (CFT), ammonia (NH3) is a stronger field ligand compared to water (H2O). This is because NH3 has a higher tendency to donate electron pairs due to its electronegativity and molecular structure. - **Conclusion**: The statement that NH3 is a relatively strong field ligand while H2O is a weak field ligand is true. 3. **Analyze the Color Change**: - The complex \([Cu(H_2O)_4]^{2+}\) is typically light blue, while \([Cu(NH_3)_4]^{2+}\) is dark blue. The change in ligands affects the crystal field splitting, leading to a change in color. - **Conclusion**: The statement about the color change from light blue to dark blue is correct. 4. **Determine the Geometry and Magnetic Properties of \([Cu(NH_3)_4]^{2+}\)**: - Copper in the +2 oxidation state has a d9 electronic configuration. In the presence of strong field ligands like NH3, the electrons will pair up, leading to a square planar geometry rather than tetrahedral. - The square planar geometry is associated with dsp2 hybridization, and since there are no unpaired electrons in the d-orbitals, the complex is actually diamagnetic. - **Conclusion**: The statement that \([Cu(NH_3)_4]^{2+}\) has a tetrahedral structure and is paramagnetic is false. ### Final Answer: The statement that is not true for the reaction is: - **Option 4**: "Copper \([Cu(NH_3)_4]^{2+}\) has a tetrahedral structure and it is paramagnetic."

To determine which statement is not true for the given reaction: \[ [Cu(H_2O)_4]^{2+} + 4NH_3 \rightleftharpoons [Cu(NH_3)_4]^{2+} + 4H_2O \] we will analyze each statement provided. ### Step-by-Step Solution: ...
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Identify the incorrect statements about [Cu(NH_(3))_(4)]^(2+)

In the following question, a statement of assertion is followed by a statement of reason . Mark the correct choice. Assertion : [Cu(NH_(3))_(4)]^(2+) is coloured while [Cu(CN)_(4)]^(3-) is colourless . Reason : [Cu(NH_(3))_(4)]^(2+) has dsp^(2) hydridisation

In the reaction: [Cu(H_(2)O)_(3)(OH)]^(+) + [AI(H_(2)O)_(6)]^(3+) to [Cu(H_(2)O)_(4)]^(2+) + [AI(H_(2)O)_(5)(OH)]^(2+)

Indicate the oxidation state of the central metal ion in each of the following complex (a) [Cu(NH_(3))_(4)]^(2+) (b) [Cu(Br_(4))]^(2-) (c ) [Cu(CN)_(2)]^(Θ) (d) [Cu(NH_(3))_(4)CO_(3)]^(o+) (e) [PtCI_(4)]^(2-) (f) [Co(NH_(3))_(2)(NO_(2))_(4)]^(Θ) (g) Fe(CO)_(5)) (h) [ZnCI_(4)]^(2-) (i) [Fe(en)_(3)]^(2+) .

When an excess of ammonia solution is added to CuSO_(4) which solution is formed (a) [Cu(NH_(3))_(2)]^(2+) (b) [Cu(NH_(3))_(4)]^(o+) (c ) [Cu(NH_(3))_(2)]^(o+) (d) [Cu(NH_(3))_(4)]^(2+) .

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