`[CoCl_(2)(NH_(3))_(4)]^(+)+Cl^(-) to [CoCl_(3)(NH_(3))_(3)]+NH_(3)`. If in this reaction two isomers of the produt are obtained, which is true for the iniital (reactant) complex:

Options

A. compound is in cis-form
B. compound is in trans-form
C. compound is in both (cis and trans)
D. can't be predicted

Explanation

To solve the question regarding the initial complex `[CoCl₂(NH₃)₄]⁺` and its isomers, we will follow these steps:

### Step 1: Understand the Reactant Complex
The reactant complex is `[CoCl₂(NH₃)₄]⁺`. This indicates that cobalt (Co) is coordinated with two chloride ions (Cl⁻) and four ammonia (NH₃) ligands.

### Step 2: Determine Possible Isomers
In coordination chemistry, the arrangement of ligands around the central metal ion can lead to different isomers. For octahedral complexes like `[CoCl₂(NH₃)₄]⁺`, we can have:
- **Cis Isomer**: where the similar ligands (in this case, Cl⁻) are adjacent to each other.
- **Trans Isomer**: where the similar ligands are opposite each other.

### Step 3: Analyze the Ligand Arrangement
In the case of `[CoCl₂(NH₃)₄]⁺`, we can visualize the arrangement of ligands:
- If we place the two chloride ions on adjacent vertices, we get the **cis** form.
- If we place the two chloride ions opposite each other, we get the **trans** form.

### Step 4: Conclusion on the Reactant Complex
Since it is possible to have both cis and trans arrangements for the ligands in the initial complex, we conclude that the reactant complex can exist in both forms.

### Final Answer
The correct statement regarding the initial complex `[CoCl₂(NH₃)₄]⁺` is that it can be both cis and trans.