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Which of the following complex compound ...

Which of the following complex compound exhibits geometrical isomerism?

A

`[Fe(DMG)_(2)]`

B

`[Be(gly)_(2)]`

C

`[PdClBr(gly)]`

D

`[Cd(NH_(3))Cl(gly)]`

Text Solution

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The correct Answer is:
To determine which of the given complex compounds exhibits geometrical isomerism, we will analyze each compound based on its structure and hybridization. ### Step 1: Identify the Compounds We have four complex compounds to evaluate: 1. Fe(DMG)₂ 2. Be(glycinato)₂ 3. PdClBr(glycinato) 4. Cd(NH₃)Cl(glycinato) ### Step 2: Analyze Each Compound #### Compound 1: Fe(DMG)₂ - **Structure**: DMG (Dimethylglyoxime) is a bidentate ligand. - **Oxidation State**: Fe is in the oxidation state 0, leading to a configuration of 3d⁶ 4s². - **Hybridization**: This complex will undergo sp³ hybridization. - **Geometrical Isomerism**: Since it is sp³ hybridized, it forms a tetrahedral geometry, which does not exhibit geometrical isomerism. #### Compound 2: Be(glycinato)₂ - **Structure**: Glycinato is also a bidentate ligand. - **Hybridization**: This complex will also form an sp³ hybridized tetrahedral complex. - **Geometrical Isomerism**: Similar to the first compound, tetrahedral complexes do not exhibit geometrical isomerism. #### Compound 3: PdClBr(glycinato) - **Structure**: This complex contains a square planar arrangement due to the presence of a transition metal (Pd). - **Oxidation State**: Pd is in the +2 oxidation state. - **Hybridization**: This complex will undergo d²sp³ hybridization, resulting in a square planar geometry. - **Geometrical Isomerism**: Square planar complexes can exhibit geometrical isomerism due to the arrangement of ligands around the central metal ion. #### Compound 4: Cd(NH₃)Cl(glycinato) - **Hybridization**: This complex is also sp³ hybridized, leading to a tetrahedral geometry. - **Geometrical Isomerism**: As with the previous tetrahedral complexes, this one does not exhibit geometrical isomerism. ### Step 3: Conclusion Based on the analysis, the only compound that exhibits geometrical isomerism is **PdClBr(glycinato)** (Option C). ### Final Answer The complex compound that exhibits geometrical isomerism is **C. PdClBr(glycinato)**. ---

To determine which of the given complex compounds exhibits geometrical isomerism, we will analyze each compound based on its structure and hybridization. ### Step 1: Identify the Compounds We have four complex compounds to evaluate: 1. Fe(DMG)₂ 2. Be(glycinato)₂ 3. PdClBr(glycinato) 4. Cd(NH₃)Cl(glycinato) ...
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VK JAISWAL ENGLISH-CO-ORDINATION COMPOUNDS-LEVEL 2
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