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In which case racemic mixture is obtaine...

In which case racemic mixture is obtained on mixing its mirror images (d & l form) is 1:1 molar ratio:

A

trans-`[Co(gly)_(3)]`

B

`[Ni(DMG)_(2)]`

C

cis-`[Cu(gly)_(2)]`

D

`[Zn(en)(gly)]^(+)`

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To determine in which case a racemic mixture is obtained when mixing its mirror images (dextro and levo forms) in a 1:1 molar ratio, we need to analyze the optical activity of the given compounds. A racemic mixture is formed when equal amounts of two enantiomers (dextro and levo forms) are combined, resulting in a compound that is optically inactive. ### Step-by-Step Solution: 1. **Understanding Optical Activity**: - A compound is optically active if it has a non-superimposable mirror image. This means that when you place a mirror next to the compound, the image cannot be perfectly aligned with the original compound. - For a compound to be optically active, it must not have any plane of symmetry or point of symmetry. 2. **Analyzing the First Option - Trans Cobalt Glycerin Thrice**: - The structure involves glycerin (NH2CH2COO-) ligands. For simplicity, we represent it as N-O. - In the trans configuration, the ligands are arranged such that there is no plane of symmetry. - When we take the mirror image, it results in a non-superimposable image, indicating that it is optically active. - Therefore, if we mix equal amounts of the dextro and levo forms, we obtain a racemic mixture. 3. **Analyzing the Second Option - Ni(DMG)2**: - DMG (Dimethylglyoxime) has two nitrogen donor atoms. - This compound has a plane of symmetry, making it optically inactive. - Since it cannot form dextro and levo forms, it cannot produce a racemic mixture. 4. **Analyzing the Third Option - Cis Glycerin Twice**: - In this case, the central atom is copper, and the arrangement of ligands is such that there are two identical ligands adjacent to each other. - This creates a plane of symmetry, making it optically inactive. - Thus, it cannot form a racemic mixture. 5. **Analyzing the Fourth Option - Zinc Ethylene Diamine**: - Ethylene diamine has two nitrogen donor atoms and is coordinated with glycerin. - This compound also has a plane of symmetry, rendering it optically inactive. - Therefore, it cannot produce a racemic mixture. ### Conclusion: The only compound that can form a racemic mixture when mixing its mirror images in a 1:1 molar ratio is **Trans Cobalt Glycerin Thrice**.

To determine in which case a racemic mixture is obtained when mixing its mirror images (dextro and levo forms) in a 1:1 molar ratio, we need to analyze the optical activity of the given compounds. A racemic mixture is formed when equal amounts of two enantiomers (dextro and levo forms) are combined, resulting in a compound that is optically inactive. ### Step-by-Step Solution: 1. **Understanding Optical Activity**: - A compound is optically active if it has a non-superimposable mirror image. This means that when you place a mirror next to the compound, the image cannot be perfectly aligned with the original compound. - For a compound to be optically active, it must not have any plane of symmetry or point of symmetry. ...
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