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An isomerr of the complex CoBrCl(2)(en)(...

An isomerr of the complex `CoBrCl_(2)(en)_(2)(H_(2)O)`, on reaction with concentrated `H_(2)SO_(4)` (dehydrating agent), suffers no loss in weight and on reaction with `AgNO_(3)` solution it gives only white precipitate, which is soluble in `NH_(3)` solution.
Q. The incorrect statement about complex is:

A

It can show geometrical isomerism

B

cis isomer is optically active

C

Trans isomer is optically active

D

it can exhibit solvate isomerism

Text Solution

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The correct Answer is:
To solve the question regarding the complex `CoBrCl₂(en)₂(H₂O)`, we need to analyze the information given and determine the incorrect statement about the complex. Let's break it down step by step. ### Step 1: Understand the Complex The complex in question is `CoBrCl₂(en)₂(H₂O)`. Here, `Co` is cobalt, `Br` is bromine, `Cl` is chlorine, `en` is ethylenediamine (a bidentate ligand), and `H₂O` is water. ### Step 2: Analyze the Reaction with Concentrated `H₂SO₄` The complex reacts with concentrated sulfuric acid (H₂SO₄), which is a dehydrating agent. The problem states that there is no loss in weight during this reaction. This indicates that the water molecule (H₂O) must be coordinated to the cobalt ion, meaning it is part of the coordination sphere. If it were outside, we would expect a loss in weight due to the removal of water. ### Step 3: Analyze the Reaction with `AgNO₃` When the complex reacts with silver nitrate (AgNO₃), it produces a white precipitate that is soluble in ammonia (NH₃). The white precipitate here is likely silver chloride (AgCl), which forms when chloride ions (Cl⁻) are present. For AgCl to precipitate, the chloride must be outside the coordination sphere. ### Step 4: Determine the Isomerism Given that the chloride ion is outside the coordination sphere and the water molecule is inside, this indicates that the complex exhibits ionization isomerism. The isomer where Cl is outside and H₂O is inside would be an ionization isomer of the original complex. ### Step 5: Identify Incorrect Statements Now, we need to evaluate potential statements about the complex to find the incorrect one. Based on our analysis: 1. The complex has water inside the coordination sphere. 2. The complex forms a white precipitate with AgNO₃, indicating chloride is outside the coordination sphere. 3. The complex exhibits ionization isomerism due to the exchange of ligands between the coordination sphere and outside. ### Conclusion The incorrect statement about the complex would likely be one that contradicts our findings about the positions of the ligands or the nature of the isomerism.

To solve the question regarding the complex `CoBrCl₂(en)₂(H₂O)`, we need to analyze the information given and determine the incorrect statement about the complex. Let's break it down step by step. ### Step 1: Understand the Complex The complex in question is `CoBrCl₂(en)₂(H₂O)`. Here, `Co` is cobalt, `Br` is bromine, `Cl` is chlorine, `en` is ethylenediamine (a bidentate ligand), and `H₂O` is water. ### Step 2: Analyze the Reaction with Concentrated `H₂SO₄` The complex reacts with concentrated sulfuric acid (H₂SO₄), which is a dehydrating agent. The problem states that there is no loss in weight during this reaction. This indicates that the water molecule (H₂O) must be coordinated to the cobalt ion, meaning it is part of the coordination sphere. If it were outside, we would expect a loss in weight due to the removal of water. ...
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An isomerr of the complex CoBrCl_(2)(en)_(2)(H_(2)O) , on reaction with concentrated H_(2)SO_(4) (dehydrating agent), suffers no loss in weight and on reaction with AgNO_(3) solution it gives only white precipitate, which is soluble in NH_(3) solution. Q. The correct formula of the complex is:

In coordination chemistry there are a variety of methods applied to find out the structure of complexes.One method involves treating the complex with known reagents and from the nature of reaction, the formula of the complex can be predicted.An isomer of the complex Co(en)_2(H_2O)Cl_2Br ,on reaction with concentrated H_2SO_4 (dehydrating agent) it suffers loss in weight and on reaction with AgNO_3 solution it gives a white precipitate which is soluble in NH_3 (aq). The correct formula of the complex is :

An isomer of the complex Co(en)_(2)(H_(2)O)IC l_(2) , on reaction with concentrated H_(2)SO_(4) , it suffers loss in weight and on reaction with AgNO_(3) solution gives a yellow precipitated which is isoluble in NH_(3) solution. Q. If all the ligandsin the co-ordination sphere of the above complex are replaced by CN^(-) ion, then the magnetic moment of the complex ion will be:

An isomer of the complex Co(en)_(2)(H_(2)O)IC l_(2) , on reaction with concentrated H_(2)SO_(4) , it suffers loss in weight and on reaction with AgNO_(3) solution gives a yellow precipitated which is isoluble in NH_(3) solution. Q. Total number of space isomers of the formula of the above complex is:

In coordination chemistry there are a variety of methods applied to find out the structure of complexes.One method involves treating the complex with known reagents and from the nature of reaction, the formula of the complex can be predicted.An isomer of the six coordination number complex Co(en)_2(H_2O)Cl_2Br ,on reaction with concentrated H_2SO_4 (dehydrating agent) it suffers loss in weight and on reaction with AgNO_3 solution it gives a white precipitate which is soluble in NH_3 (aq). If one mole of original complex is treated with excess Pb(NO_3)_2 solution, then the number of moles of white precipitate (of PbCl_2 ) formed will be :

An isomer of the complex Co(en)_(2)(H_(2)O)IC l_(2) , on reaction with concentrated H_(2)SO_(4) , it suffers loss in weight and on reaction with AgNO_(3) solution gives a yellow precipitated which is isoluble in NH_(3) solution. Q. If one mole of original is treated with excess Pb(NO_(3))_(2) solution, then the number of moles of white precipitate formed will be

Concentrated H_(2)SO_(4) will not dehydrate the following complex:

on reaction with concentrated H2SO4, it suffers loss in weight and on reaction with AgNO3 solution gives a yellow precipitated which is isoluble in NH3 solution If all the ligands in the coordination sphere of the Co(en)_2(H_2O)Cl_2 I complex be replaced by F^(bar) , then the magnetic moment of the complex ion (due to spin only) will be :

A whiite crystalline salt imparts a violet colour to a Bunsen flame, and with hot concentrated H_(2)SO_(4) , forms a pungent gas. On treatment with an AgNO_(3) solution, this gas forms a white precipitate readily soluble in NH_(3) . The whiite crystalline salt may be:

Give a reason why concentrated and not dilute H_(2)SO_(4) - behaves as an oxidising and a dehydrating agent.

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