Home
Class 12
CHEMISTRY
Assertion: Acidified [Cu(NH(3))(4)]^(2+)...

Assertion: Acidified `[Cu(NH_(3))_(4)]^(2+) and [Cu(H_(2)O)_(4)]^(2+)` both react with `K_(4)[Fe(CN)_(6)]` to give brown ppt.
Reason: both complexes are blue in colour of little different shade.

A

If assertion is true but the reason is false

B

If assertion is false but reason is true

C

If both assertion and reason are true and the reason is the correct explanation of assertion

D

If both assertion and reason are true but reason is not the correct explanation of assertion

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided, and determine their validity as well as the relationship between them. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that acidified \([Cu(NH_3)_4]^{2+}\) and \([Cu(H_2O)_4]^{2+}\) both react with \(K_4[Fe(CN)_6]\) to give a brown precipitate. - Copper in both complexes is in the +2 oxidation state (\(Cu^{2+}\)). 2. **Reaction with Potassium Ferrocyanide**: - When \(Cu^{2+}\) ions react with potassium ferrocyanide \((K_4[Fe(CN)_6])\), they form a complex, specifically \([Cu_2Fe(CN)_6]\), which is known to precipitate as a brown solid. - Therefore, the assertion is **True**. 3. **Understanding the Reason**: - The reason states that both complexes are blue in color but of slightly different shades. - The color of coordination complexes is influenced by the presence of unpaired electrons and the nature of the ligands. - Both complexes contain \(Cu^{2+}\) which has a \(d^9\) electronic configuration (since \(Cu\) has a configuration of \( [Ar] 4s^1 3d^{10} \) and loses one \(4s\) and one \(3d\) electron to form \(Cu^{2+}\)). 4. **Color Explanation**: - The color difference arises from the ligand field splitting and the arrangement of unpaired electrons in the \(d\) orbitals. - \([Cu(H_2O)_4]^{2+}\) and \([Cu(NH_3)_4]^{2+}\) both exhibit different ligand field strengths, leading to slightly different shades of blue. - Thus, the reason is also **True**. 5. **Evaluating the Relationship**: - The reason explains the color difference but does not explain why these complexes react with potassium ferrocyanide to form a brown precipitate. - Therefore, while both statements are true, the reason does not serve as a correct explanation for the assertion. ### Conclusion: - The assertion is true, the reason is true, but the reason is not the correct explanation for the assertion. ### Final Answer: Both assertion and reason are true, but the reason is not the correct explanation of the assertion.
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|42 Videos
  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise LEVEL 2|144 Videos
  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise MATCH THE COLUMN|36 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|54 Videos
  • d-BLOCK ELEMENTS

    VK JAISWAL ENGLISH|Exercise ASSERTION-REASON TYPE QUESTIONS|32 Videos

Similar Questions

Explore conceptually related problems

CuSO_(4)+NH_(3)(excess) to [Cu(NH_(3))_(4)]^(2+)

K_(4)[Fe(CN)_(6)] reacts with ozone is give:

With Zn^(2+) ions [Fe(CN)_(6)]^(4-) ions gives …ppt

Fe^(2+) does not give blue colour with K_(4)[Fe(CN)_(6)] but on its reaction with (X) ,blue colour oppears (X) can be

[Fe(H_(2)O)_(6)]^(2+) and [Fe(CN)_(6)]^(4-) differ in :

[Fe(H_(2)O)_(6)]^(2+) and [Fe(CN)_(6)]^(4-) differ in :

CuSO_(4) reacts with NH_(3) to give blue complex of

When K_(4)[Fe(CN)_(6)] is treated with FeCI_(3) a blue colour is obtained It is due to the formation of .

[Cu(NH_3)_4]^(2+) ion is coloured while [Cu(CN)_4]^(3-) ion is colourless why ?

[Fe(CN)_(6)]^(4-) and [Fe(H_(2)O)_(6)]^(2+) are of different colours in dilute solutions why?

VK JAISWAL ENGLISH-CO-ORDINATION COMPOUNDS-ASSERTION-REASON TYPE QUESTIONS
  1. Assertion: Oxidation state of Fe in Fe(CO)(5) is zero. Reason: Syner...

    Text Solution

    |

  2. Assertion: Zeise's salt is a pi-bonded organometallic compound. Reas...

    Text Solution

    |

  3. Assertion: [CoCl(3)(NH(3))(3)] does not give white precipitate with Ag...

    Text Solution

    |

  4. Assertion: Transition metal ion forming octahedral complexes undergo s...

    Text Solution

    |

  5. Assertion: Complex ion [Co(NH(3))(6)]^(2+) is readily oxidized to [Co(...

    Text Solution

    |

  6. Assertion: Hydrazine is a neutral ligand. Reason: It has two N as do...

    Text Solution

    |

  7. Assertion: Complex anion [Re(2)Cl(8)]^(2-) has one delta-bond, one sig...

    Text Solution

    |

  8. Assertion: In N(2) Molecule, any N-atom can coordinate with central at...

    Text Solution

    |

  9. Assertion: In N(2)H(4), any one N-atom can coordination with central m...

    Text Solution

    |

  10. Assertion: [Ti(H(2)O)(6)]^(4+) is coloured while [Sc(H(2)O)(6)]^(3+) i...

    Text Solution

    |

  11. Assertion: Acidified [Cu(NH(3))(4)]^(2+) and [Cu(H(2)O)(4)]^(2+) both ...

    Text Solution

    |

  12. Assertion: [Fe(EDTA)]^(-) complex is octahedral in shape. Reason: ED...

    Text Solution

    |

  13. STATEMENT-1: Tetrahedral complexes with chiral structure exhibit optic...

    Text Solution

    |

  14. Assertion: Oxidation state of Fe in Fe(CO)(5) is zero. Reason: Syner...

    Text Solution

    |

  15. Assertion: Zeise's salt is a pi-bonded organometallic compound. Reas...

    Text Solution

    |

  16. Assertion: [CoCl(3)(NH(3))(3)] does not give white precipitate with Ag...

    Text Solution

    |

  17. Assertion: Transition metal ion forming octahedral complexes undergo s...

    Text Solution

    |

  18. Assertion: Complex ion [Co(NH(3))(6)]^(2+) is readily oxidized to [Co(...

    Text Solution

    |

  19. Assertion: Hydrazine is a neutral ligand. Reason: It has two N as do...

    Text Solution

    |

  20. Assertion: Complex anion [Re(2)Cl(8)]^(2-) has one delta-bond, one sig...

    Text Solution

    |