All alkali metals dissolve in anhydrous liquid ammonia to give blue colour solution. It is the ammoniated electron which is reponsible for the blue colour of the solution, and the electrical conductivity is due to the ammoniated cation, `[M(NH_(3))_(x)]^(+)` as well as the ammoniated electron,` [e(NH_(3))_(y)]^(-)`, value of x and y depend on the extent of solvation by `NH_(3)`. Dilute solutions are paramagnetic due to free ammoniated electrons.
Q. Ammoniated solutions of alkali metals are reducing agents due to the presence of free ammoniated or solvated electrons that can reduce:
(I)`O_(2) "to" O_(2)^(2-)` (II) `K_(2)[Ni(CN)_(4)] " to "K_(4)[Ni(CN)_(4)]`
(III) Aromatic ring (IV) Non-terminal alkyne
Choose the correct code:

Options

A. III and IV
B. II and III
C. I, II, III and IV
D. I, III and IV

Explanation

To solve the question regarding the reducing ability of ammoniated solutions of alkali metals, we will analyze the given reactions and determine which species can be reduced by the ammoniated electrons.

### Step-by-Step Solution:

1. **Understanding Ammoniated Solutions**:
- Alkali metals dissolve in anhydrous liquid ammonia to form a blue-colored solution. This blue color is due to the presence of free ammoniated electrons, denoted as `[e(NH₃)ₓ]⁻`, and ammoniated cations, `[M(NH₃)ₓ]⁺`.

2. **Identifying the Reducing Agent**:
- The ammoniated electrons are reducing agents because they can donate electrons to other species. This means they can reduce other compounds by providing them with electrons.

3. **Analyzing the Reduction Reactions**:
- **(I) Reduction of O₂ to O₂²⁻**:
- The reduction of molecular oxygen (O₂) to superoxide (O₂²⁻) involves the gain of electrons. Since ammoniated electrons can donate electrons, this reaction is feasible.

- **(II) Reduction of K₂[Ni(CN)₄] to K₄[Ni(CN)₄]**:
- In this case, we need to analyze the oxidation states. Nickel in K₂[Ni(CN)₄] is in the +2 oxidation state. When reduced to K₄[Ni(CN)₄], nickel goes to a 0 oxidation state, indicating it gains 2 electrons. Thus, this reduction is also feasible with ammoniated electrons.

- **(III) Reduction of Aromatic Ring**:
- Aromatic compounds can undergo reduction, converting double bonds into single bonds, leading to saturated compounds. Ammoniated electrons can facilitate this reduction, making this reaction possible.

- **(IV) Reduction of Non-terminal Alkyne**:
- Non-terminal alkynes can also be reduced to alkenes or alkanes. The presence of ammoniated electrons allows for this reduction to occur.

4. **Conclusion**:
- All four reactions (I, II, III, IV) can be reduced by ammoniated electrons. Therefore, the correct answer is that all options are valid reducing reactions.

### Final Answer:
The correct code is **C (I, II, III, IV)**.