Sodium sulphite `(Na_(2)SO_(3))` is added to meat as a preservative. The presence of `Na_(2)SO_(4)` can be detected by adding dil. `H_(2)SO_(4)` when the pungent smelling gas evolved turns the lime water milky. The gas evolved was detected as sulphur dioxide. The `SO_(2) " to "SO_(4)^(2-)` in titration.
`SO_(2)+2H_(2)O+I_(2) to 4H^(+)+SO_(4)^(2-)+2I^(-)`
In order to check the results of titration, excess barium chloride is added to the final solution. The resulting precipitate is collected and weighed.
Q. Which of the following compounds is formed, when `Na_(2)SO_(3)` is boiled with sulphur.

Options

A. `Na_(2)SO_(4)`
B. `Na_(2)S_(4)O_(5)`
C. `Na_(2)S_(4)O_(6)`
D. `Na_(2)S_(4)O_(3)`

Answer

To determine the compound formed when sodium sulphite `(Na₂SO₃)` is boiled with sulphur, we can follow these steps:

### Step 1: Understand the Reactants
- We have sodium sulphite `(Na₂SO₃)` and elemental sulphur `(S)` as the reactants.

### Step 2: Identify the Reaction
- When sodium sulphite is boiled with sulphur, a chemical reaction occurs where sulphur reacts with sodium sulphite. The expected product of this reaction is sodium thiosulphate `(Na₂S₂O₃)`.

### Step 3: Write the Balanced Chemical Equation
- The balanced equation for the reaction can be written as:
\[ Na₂SO₃ + S \rightarrow Na₂S₂O₃ \]
- This indicates that one mole of sodium sulphite reacts with one mole of sulphur to produce one mole of sodium thiosulphate.

### Step 4: Conclusion
- The compound formed when sodium sulphite is boiled with sulphur is sodium thiosulphate `(Na₂S₂O₃)`.

### Final Answer
- The correct compound formed is **sodium thiosulphate `(Na₂S₂O₃)`**.

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