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Assertion: Be(OH)(2) dissolves in excess...

Assertion: `Be(OH)_(2)` dissolves in excess NaOH solution.
Reason: `Be(OH)_(2)` is an acidic compound.

A

If both assertion and reason are true and the reason is the correct explanation of assertion

B

If both assertion and reason are true and the reason is not the correct explanation of assertion

C

If assertion is false but reason is true

D

If assertion is true but the reason is false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Analyze the Assertion The assertion states that `Be(OH)_(2)` (beryllium hydroxide) dissolves in excess NaOH solution. - **Explanation**: Beryllium hydroxide is known to be amphoteric, meaning it can react with both acids and bases. When beryllium hydroxide is added to an excess of sodium hydroxide (a strong base), it reacts to form a soluble complex ion, specifically the beryllate ion, `Be(OH)₄²⁻`. This confirms that the assertion is true. ### Step 2: Analyze the Reason The reason states that `Be(OH)_(2)` is an acidic compound. - **Explanation**: While beryllium hydroxide does exhibit some acidic properties, it is more accurately described as amphoteric. This means it can react with both acids and bases. Therefore, the statement that it is purely an acidic compound is incorrect. ### Step 3: Conclusion - Since the assertion is true (beryllium hydroxide does dissolve in excess NaOH) and the reason is false (beryllium hydroxide is not solely an acidic compound but amphoteric), we can conclude that the correct option is that the assertion is true and the reason is false. ### Final Answer The correct option is: Assertion is true, Reason is false. ---

To solve the question, we need to analyze both the assertion and the reason provided. ### Step 1: Analyze the Assertion The assertion states that `Be(OH)_(2)` (beryllium hydroxide) dissolves in excess NaOH solution. - **Explanation**: Beryllium hydroxide is known to be amphoteric, meaning it can react with both acids and bases. When beryllium hydroxide is added to an excess of sodium hydroxide (a strong base), it reacts to form a soluble complex ion, specifically the beryllate ion, `Be(OH)₄²⁻`. This confirms that the assertion is true. ### Step 2: Analyze the Reason ...
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