Chloroplatinic acid is:

Options

A. monobasic
B. dibasic
C. tribasic
D. tetrabasic

Answer

To determine whether chloroplatinic acid is monobasic, dibasic, tribasic, or tetrabasic, we need to analyze its structure and the number of hydrogen ions it can donate upon ionization.

### Step-by-Step Solution:

1. **Identify the Chemical Formula**:
- The formula for chloroplatinic acid is \( H_2PtCl_6 \).

2. **Understand the Structure**:
- Chloroplatinic acid consists of a platinum (Pt) atom surrounded by six chloride (Cl) ions and two hydrogen (H) ions. The structure can be visualized as follows:
- \( H \) is bonded to \( Cl \) and there are four other \( Cl \) atoms bonded to \( Pt \).

3. **Determine the Ionization**:
- When chloroplatinic acid ionizes in solution, it releases hydrogen ions (\( H^+ \)). The key point here is to determine how many \( H^+ \) ions are released.
- Each molecule of chloroplatinic acid can release two \( H^+ \) ions.

4. **Classify the Acid**:
- An acid that can donate two protons (hydrogen ions) is classified as dibasic. Since chloroplatinic acid releases two \( H^+ \) ions upon ionization, it is classified as dibasic.

5. **Conclusion**:
- Therefore, chloroplatinic acid is dibasic.

### Final Answer:
Chloroplatinic acid is dibasic.

---