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The oxoanion which contains all equivale...

The oxoanion which contains all equivalent `M-O` bond is:
(I)`CrO_(4)^(2-)` (II)`MnO_(4)^(-)` (III)`Cr_(2)O_(7)^(2-)`

A

III only

B

I, II, III

C

I, II

D

I only

Text Solution

AI Generated Solution

The correct Answer is:
To determine which oxoanion contains all equivalent M-O bonds, we will analyze each of the given options: \( \text{CrO}_4^{2-} \) (chromate), \( \text{MnO}_4^{-} \) (permanganate), and \( \text{Cr}_2\text{O}_7^{2-} \) (dichromate). ### Step 1: Analyze \( \text{CrO}_4^{2-} \) (Chromate Ion) - The chromate ion has the formula \( \text{CrO}_4^{2-} \). - In its structure, chromium is bonded to four oxygen atoms. - The bonding involves resonance, where the double bonds can shift among the oxygen atoms. - As a result, all \( \text{Cr-O} \) bonds are equivalent due to resonance, and they exhibit partial double bond character. ### Step 2: Analyze \( \text{MnO}_4^{-} \) (Permanganate Ion) - The permanganate ion has the formula \( \text{MnO}_4^{-} \). - Similar to chromate, manganese is bonded to four oxygen atoms. - The structure also allows for resonance, where the double bonds can shift among the oxygen atoms. - Therefore, all \( \text{Mn-O} \) bonds are equivalent due to resonance, exhibiting partial double bond character. ### Step 3: Analyze \( \text{Cr}_2\text{O}_7^{2-} \) (Dichromate Ion) - The dichromate ion has the formula \( \text{Cr}_2\text{O}_7^{2-} \). - In this ion, there are two chromium atoms bonded to seven oxygen atoms. - The structure includes both double bonds and single bonds. Specifically, three of the bonds are equivalent (double bonds), while the remaining bond is a single bond. - The bond lengths differ: the double bonds are shorter (approximately 163 pm) compared to the single bond (approximately 179 pm), indicating that not all \( \text{Cr-O} \) bonds are equivalent. ### Conclusion - From the analysis, \( \text{CrO}_4^{2-} \) and \( \text{MnO}_4^{-} \) have all equivalent \( \text{M-O} \) bonds due to resonance. - \( \text{Cr}_2\text{O}_7^{2-} \) does not have all equivalent bonds because of the presence of both double and single bonds. Thus, the correct answer is that the oxoanions which contain all equivalent \( \text{M-O} \) bonds are \( \text{CrO}_4^{2-} \) and \( \text{MnO}_4^{-} \). ### Final Answer The oxoanion which contains all equivalent \( \text{M-O} \) bonds is: (I) \( \text{CrO}_4^{2-} \) and (II) \( \text{MnO}_4^{-} \).
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