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Fe(OH)(3)darr+NaOH(excess)toNo reaction...

`Fe(OH)_(3)darr+NaOH(excess)to`No reaction

A

For precipitate formation reaction

B

For precipitate dissolution reaction

C

For precipitate exchange reaction

D

For no reaction

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The correct Answer is:
To solve the question regarding the reaction of Fe(OH)₃ with excess NaOH, we will analyze the situation step by step. ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactants in the reaction are Iron(III) hydroxide, Fe(OH)₃, and sodium hydroxide, NaOH. 2. **Understand the Nature of the Reactants**: Fe(OH)₃ is a precipitate, which means it is an insoluble compound that can settle at the bottom of a container. NaOH is a strong base and is soluble in water. 3. **Consider the Reaction Conditions**: The question states that NaOH is in excess. This means there is more NaOH present than is needed to react with Fe(OH)₃. 4. **Analyze Possible Reactions**: In general, when a strong base like NaOH is added to a precipitate like Fe(OH)₃, one might expect a reaction where the precipitate could dissolve or form a complex. However, in this case, the question indicates that there is "no reaction." 5. **Conclusion**: Since there is no new product formed and the Fe(OH)₃ does not dissolve in excess NaOH, we conclude that this is a case of "no reaction." The precipitate remains unchanged, and no new compounds are created. ### Final Answer: The reaction of Fe(OH)₃ with excess NaOH results in **no reaction**. ---
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